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• . ., . . • - ' POMP SELECTIOIN•FRDCED E ' •• <br /> 1. D eteTn ne punt . 'capacity: - <br />,,A. Gravity distri•. <br /> tion <br /> 1. •Mtnfsnum'required discharge is 10 gpm • <br /> 2 Maximsim ss: -•: ?'ge is 4S,gp'n• For other <br /> establishments atle= 1014:grestet thar the water supply rate, • <br /> • e rate at�vhici effl•ent will flow out of the <br /> but no faster than ,. '� • • • <br /> disti�'bution device. • <br /> $.-Pressure distrib . Ilan- .. . <br /> See pressure distri 'tion.work sheet . <br /> From'A or B.'Sellecte'.'pump capacity: Lir) • gpm • <br /> • ead re uirements: • <br /> Z..Determine pump son treatment system <br /> A. Elevation difference be' een pump and point of discharge? &p. , .f.lscharge <br /> eet • • <br /> ayttsl <br /> t?(See Figure at right Special Head Requirements) total .Ipe <br /> B. Special head'requirem 8u P 1e 2A,elevation <br /> eet . ' Inlet :i'''""'°_ '' • difference <br />' C. calculate Friction loss • •• • pipe j • <br /> 1. Seiett.pipe•diameter' • i ,i f 140 <br /> _ 2. Enter Figure'E-9 with :•,.. • (1A or B).and pipe diameter(C1). <br /> � <br /> Read friction•loss•in•f- tper 100 feetfrtsm Figure E-9• ' . • Special 'Hid Requirements <br /> • ' Gravity Distribution 0 ft <br /> Friction•Loss=• - 4 ft/•IOOft of pipe , <br /> • privity bistbuti ion 5 ft <br /> 3. Determine total pipe 1 . : from pump discharge to soil treatment <br /> discharge point.Es. • =to by adding 25 percent to pipe length for . <br /> fitting loss.Total.pip;length times 1.25=equivalent pipe length £-9 Frlctlon Loss in:Plastic Pipe <br /> ____4,2(2...-„feet x 1.2.5•T • -et Par•100 feet <br /> 4. CaTulate'total friction ass by multiplying friction loss(C2) •bPipe tnaldiametern <br /> in ft/100.ft,by:•.the e• �• t.pipe length(C3)and divide.by 100. •low rete 1 • <br /> ft/100ft x +100= 3 ft gpm <br /> D. Total head required is.• a sum of elevation difference(A);specig: • 2b ' 2:47 0.73 0.11' <br /> 25 3.73 1.11 0.16 <br /> head requirenients�.(B), ` d'tota1���lo�s(C4) 35 5.23 1.1551 0.23 <br /> + f 35 . 6.96 ;.2.06 0.30 <br /> Total head: •/‘ • feet 40 • 8.91 2.64 0.39 <br /> 45 " ' 11.07 3.28 8.48 <br /> 3. Pump selection 13.46 3.99 0.58 <br /> 55 4.76 0.70 <br /> A pump must be selected to deliver at least Lir) •$pm • • • - 60 5.60 0.82 <br /> (1A or B)with at least_k_feet of total head(2D) 0 • 6.48 0.95 <br /> 7.44 1;09 <br /> ' I.hereby certify that.I have c . pleted this work•iri accordance•wittiapplicable oidinances,,rules and laws. <br /> �' • (sigi'ature) 1 ). • .•(license#) . • (-) 1'01.1- (date) <br /> __,.4-&--__. 6. <br />