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• • SELECTIOiN•FROCEDURE ' • • <br /> 1. Determine pu.mto rapacity: • <br />--A. Gravity distri tion • . . <br /> 1. 'Minimum: equired charge is 10 gpm <br /> 2. Maximum suggest* 'discharge is 45 gpm. For other <br /> establish e a ie •. 10 %:geket#ail the water supply rate, <br /> • <br /> • blit no faster titan a rate at which effluent will flow out of the . <br /> • <br /> distribution device. •• • . •• . • <br />' •B....Pressure distrib tion • <br /> See pressure distri . .tion.work skeet <br /> • <br /> From A ar B.SeIecte 'pump capacity: ' gpm • • <br /> •2..Determine pump ead are�quirements: soil treatment system <br /> • <br /> A.Elevation different*b een pump and point of discharge? • p. ,�• .i charge <br /> �' .• •eet . 9y.) <br /> B. Special head'requirem 't?(See Figure at right-Special Dead Requirements) . <br /> 2A.elevation <br /> ____::::_.7.-feet • Inlet : difference <br /> C. Calculate Friction loss " •p� ''; • <br /> 1. Select.pipe.�?rieter' a.v In i1 a 11 l <br /> 2. Enter Figure'E-9 with gpm(1A or B).and pipe diameter(C1). , • <br /> per9 • Special Head Requirements <br /> Read frict3on�loss�i:x•feetp Figure E- • • Gravity Distribution 0 ft <br /> Frictiort'I:oss f.- ' )I. ft/100ft of pipe ' pressure b101b�tion 5 ft <br /> 3. Determine total pipe lenges from pump discharge to soil treatment . • <br /> discharge point.Estimate by adding 25 percent to pipe length for . <br /> fitting loss.Total pipe length times 1.25=equivalent pipe length • <br /> fl.9:Fdctiion Loss in Plastic Pipe <br /> __ E, feet x t.2.5,r 13' feet. Fer 100 feet <br /> 4. Cal�ulate'total friction loss by multiplying friction loss(C2) Ripeiameter n <br /> in ft/100 ft by.•.the equiyalent pipe length(C3)and divide.by 100. •flow rate 1.5 2 •3 <br /> ft/100ft x-_.'__+100= • • I Spm <br /> D. Total head required is.the sum of eYevation difference(A);specisr 20 ' 2A7 0.73 0.11' <br /> head re ents..(B),and total friction loss(C4) <br /> 25 • 3.73 1.11 0.16 <br /> q�?n• •.30 ...5.23 1.55 0.23 <br /> •�= ft+ -- ' '---L-- ft_ 35 . 6.96 ..2.06 0.30 <br /> Total head: .1:o . feet .. 40 • 8.91 , .2.64 0,39 <br /> 45 • 11.07 3.28 0.48 <br /> 3. Purnp selection 13.46 3.99 0.58 <br /> 4.76 0.70 <br /> A pump must be selected to'deliver at least 2J gpm • • •• " 60 5.60 0.95 <br /> 0.82 <br /> (1A or B)with at least feet of total head(2D) 65 • <br /> 70 7.44 1;09 <br /> • applicable ordlriaiices, ,soles and laws. <br /> ' I hereby certify that.I have ompieted.this work•ir accordence•vyith <br /> i 5. (signature) 3c.?q (license#) S"'1 -0y (date) <br />