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. <br /> ' PROSURE DISTRIBUTION SYSTEM Geotextile fabric <br /> 1. Select numbe of perforated laterals Z . liner inch lions <br /> 2. Select perforation spacing= 3.0 ft ' . ..., :,.....,":::::.:.• <br /> . .•• ' t..,,!c..: F.'. • • <br /> PertSizing 3/16"-1/4" <br /> l <br /> 3. Since perfora 'ons should not be placed closer than 1 foot to Perf SPadng 1.5*-5' <br /> the edge of rock layer(see diagram),subtract 2 feet from <br /> the rock layer ength. E-4: Mmdnnun allowable number of 1/4-Inch perforations <br /> per'laterd to guarantee<10%.d1scharge variation <br /> C°1- -2 ft = t.0 ft perforation <br /> xoc�t +n►uw :spacing <br /> 4. Determine the umber of spaces between perforations. (feet) 1 inch .1.25 inch, .1.5•inch 2.0 Inch <br /> Divide the len (3)by perforation spacing(2)and round <br /> dawn to ne t whole number.. • • g 14 18 28 <br /> Perforati spacing=_kg_ft+ 3 ft= a.O spaces 3.0 ' 8 13 17 26 <br /> 3.3 7 12 16 ' 25 <br /> • 5. Number of p , orations is equal to.one plus the number of 40 7 11 15 23 <br /> a (4)..Check figure E-4 to assure the number of <br /> perforation spa . 5.0 6 10 14 22' <br /> perforations per• feral guarantees<10%discharge variation. <br /> • -a-0 •aces+1 =...a.L .perforations/lateral E-6: Perforation Discharge in gpm <br /> 6. A. Total numb= of perforations= perforations per lateral(5) perforation diameter <br /> times numb= of laterals(1) head inches) <br /> (feet) 3/16 7/32 1/4 <br /> 7,1 • . /lat x 3 lat= 1.3 perforations <br /> 1.00 0.42 0.56 0.74 <br /> B. Calculate the -• : e footage per perforation. 2,Ob 0.59 0.80 1.04 <br /> Should be 6-1 i sgft/perf.Does not apply to at grades. <br /> Rock bed area rock width(ft)x rock length(ft) 5.0 0.94 1.26 1.65 <br /> pft X L ss �L sgft . a use 1.0 foot for single-family homes. <br /> Square foot • ,perforation=Rock bed area+number of perfs(6) b use 2.0 feet for anvthlno else. <br /> (e0-f. sgft+ L4 perfs= 9,s: sgft/perf wwra o Lowe AT ee or IPACIAAK oarniwnoN SYSTEM <br /> 7. Determine req ' - • flow rate by multiplying the total number of <br /> perforations"(6A •by flow per perforation'(see figure E4) "ter <br /> 114`4,)102 �..w <br /> .Sam • - . x ,n 4 gpn.1/parts= 4 9 gpm • - �. <br /> 8. If laterals.are c• ected to headerpipe as shown on upper , VIZ <br /> example,to sele minimum requited lateral diameter;enter . <br /> 4 <br /> figure E- with p oration spacing(2)and number of perforations \ "d°1 <br /> per lateral(5) Set minimum diameter for • <br /> ,,,,,,, ,. Var.ne <br /> perforated lateral inches. <br /> 9. If perforated later system is attached to manifold pipe near „,,,,,..- <br /> the center,lower gram,perforated lateral length(3)and •I.. <br /> number of perfora 'ons per lateral(5)will be approximately one "..n..•, <br /> • half of that in step . Using these values,select minimum .a• , <br /> diameter for perfo ted lateral= 1/11- inches. ..OP eA <br /> I hereby certify that II have mpleted this work in accordance with applicable ordinances, rules and laws. <br /> (., A <br /> ---' (signa re) 3"19 (license#) . `S-1)-D q ' (date) <br />