|
PRESSURE DISTRYB.UTION SYSTEM Geotextile fabric
<br /> , ..
<br /> 'c';a::n;�r.0''�b'c�o••,�: a•:b�..
<br /> 1. Select number of erforated laterals �'���'��_�`'��'°�'x�;J�a`.ia��°r�.;�.�y a�p�.�:�:�,:a'{;�:�,`o`,:��:
<br /> P � �: . • �<.. . . �.. �.. . ;� ;�
<br /> - arter inch erforaHons s aced�3' ���`�������"':���''�`
<br /> . .1 .. ._..,,�.•.'�.V. �.tti:..�
<br /> ' i�".'�����t?"r,:?le.�'�,�r4,/;h,�'d'��d:.a:.� G' 'd+:'t',�,.,�%.., .�Fqj��y�.t�o:o-�oi}�..
<br /> 2. Select perforation spacing= 3.O �,H•c�;���,��,F:�.,s;,��f�.�,,:.a>.�s�;��. .;�,,<<�.°�.°�:��,r::�.r;.n:,;�o��r��.�
<br /> feet. �,:�n..h.tyR.c,,:,;,c�.�:,!�Gxu:.�l).:�%.a;��� } �"�.,lb�'s�r,�Q' a s.a
<br /> - �LU �7 ��..' U:.�b y:o"�o la�:fi�� . `o '� {�;.�.�� n... f p�o,-�'G�,�°C��
<br /> . Ti� t2:C.l':�J. .n: 4�., .r C�' c•-•� nq�..o'Cu
<br /> � o�:.:i.i�a o•�?G:l?�`CFI�1 .�ita. i�.'3r/.,.yn;o;�::i7•r;, fj�'P{�t?
<br /> . . ;C��t.5'r;c�.:
<br /> Perf Sizing 7/32"-1/4"
<br /> 3. Since perforations should not be placed closer than 1 ft. to Perf Spacing 1.5�-5�
<br /> the edge of the rock layer (see diagram),subtract 2 ft. from
<br /> the rock layer length.
<br /> Pertoratlon Dtscharges In gpm
<br /> �'2'" -2 ft• _ �� feet. perforatlbn dlameter
<br /> oc ayer �,g (nches
<br /> • � head �
<br /> � (feet) 1/8* 3/16 7/32 1/4
<br /> 4. Determine the number of spaces between perforations. �,pa 0.18 0.42 0.56 .74
<br /> Divide the length above by perforation spacing and round �
<br /> down to nearest whole number. 2•�b 0.26 0.59 0.80 1.04
<br /> . 5.0 0.41 0.94 1.26 1.65
<br /> Length perf. spacing= (ov ft, �- � �{, _ `v�?� Sp1Ces aus�t.ofoottors�n9�e-famuynomes.
<br /> • � �3� �2� b Use 2.0 feet for anything else.
<br /> 5. Number of perforations is equal to one plus.the number of ' Potentlalforplugglne
<br /> perforation spaces . _ �,
<br /> c�-O spaces + 1 - � 1 erforations/latezal M�i�number of quazter inch perEorarions pe
<br /> P lateral to guamantee<10%discharge variaHon
<br /> Perforation
<br /> 6. Multiply perforations per lateral by number of laterals to � Sgfe�g 1% 1� 2
<br /> get total number of.perforations. 2
<br /> � . 2.5 14 18 28
<br /> p—��-�—�_ .1�� perforations: 3.0 13 17 26
<br /> ater X ers ater �.� ��
<br /> 16 25
<br /> Calculate the square footage per perforation (6-10 sqft/perfl 4.0 11 15 23
<br /> System area: /c� x t�z = �,.z.o � 5.Q 1 Q 14 22
<br /> ca t� _ (�3 = �- � sqfdperf
<br /> area er ora ons
<br /> M4NIfp(,D�LOCqTEO AT ENp pf pRESS1RE 015TpIBV710N SYSiEM
<br /> 7. Determine required flow rate by multiplying, �
<br /> number of perforations by.flow per perforation " ,�„�„
<br /> r „�
<br /> � ���!�QIXl.
<br /> .�� X SP� pe1 _�gpm �/ �'�.,r��
<br /> �,,,,,v yR�l�p�.�.J�
<br /> 8. If laterals are connected to header pipe as shown on upper ���""d
<br /> example, to select minimum required lateral diameter;enter
<br /> table with per.foration spacing and number of perforations
<br /> UYOUT OF rEpI0R4TED/IPE IATENILS Nfl
<br /> per lateral. SeleCt minim �E��+E o�s*fl�B�*��„ W MOUNO
<br /> um diameter for
<br /> _/—ILIRM�IID RA�iK I?[
<br /> perforated lateral = `- � inches. �
<br /> . �2rtaca{iu�row�Qj�w„. ��� � .
<br /> � vlEw �WY K� ry ^�[I�lP'MfM'v
<br /> 9. If perforated lateral system is attached to manifold pipe near .��,o..,; .,.,�a �"`�.
<br /> b . .,..��. ti,.
<br /> the center,lower diagram,perforated lateral length and -
<br /> number of perforations per lateral will be approxirriately one ,��, ,o, `��'�j�°"""�'
<br /> half of that in step 8. Using these values,select minimum �,�^`"`"��
<br /> diameter for perforated lateral= I`�z�n��"inches. �u"""`�� �����
<br />
|