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Li. UUWNSLUNE DIKE W1U*11-1 <br />I. If landslope is 3% or more, subtract rock layer width from <br />adsorption width to obtain minimum downslope dik 'oe for <br />absorption: <br />'AL..,) ft - /0 ft feet <br />rA <br />— <br />Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation 1.0 feet <br />b. ltiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference �� \ <br />10 x C% + 100 = ." feet �--�- <br />c. Add depth of clean sand depth of clean sand for ��- <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound <br />height at upslope edge of rock layer; <br />/. o ft + 1 ft + 1 ft = 3.0 feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of 3.33 <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 3.o x 3.-3'3 = /o feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height <br />3. y + S =_3 .,'feet <br />g. Enter table on page bottom w-.1i landslope and <br />downslope dike ratio. <br />Select dike multiplier of S.y <br />h. Multiply dike multiplier by downslope mound hei ht <br />to get downslope dike width: ri x S.o = feet <br />i. Compare the values of sici ';.1 and Step G.2.h. Select the <br />greater of the two values as the downsiope dike width; <br />I'e_ feet ;.::.:.::':::: : :• :::::.........:..:::....:.:. <br />� <br />Total mound width is the sum of upslope dike Roc i u wi" <br />:t : r Y Y Y V Y Y Y V Y Y Yr�: ••' ••' <br />width plus rock layer width plus downslope <br />dike width; <br />1_ ft + / 0 f t + —4i f t = 73 feet r::.:;.+r.:{.L•.t:. r.•:.::. 'i:'•:�•'': <br />OQW WWI i—J-e�- <br />k. Total mound length is the sum of upslope <br />g f:;':•'s: twrwi;a <br />dike width plus rock layer length plus ::• :, <br />upslo-- dike width; <br />ft + _._("d ft + 1-0 f! = fS� feet <br />4.1 <br />S l <br />ll <br />7:1 <br />1 1 <br />• UoFr <br />0 <br />30 <br />40 <br />So <br />60 <br />70 <br />It. <br />10 <br />SO <br />LO <br />70 <br />I <br />S00 <br />417 <br />$2L <br />LN <br />733 <br />3Li <br />176 <br />S" <br />6S1 <br />741 <br />J <br />71� <br />13S <br />SSL <br />LIi <br />1i1 <br />'V <br />)- <br />ISI <br />5% <br />.14 <br />L10 <br />) <br />131 <br />1S1 <br />SN <br />77J <br />IIV <br />'"i <br />3.7 <br />13. <br />Sry <br />L79 <br />11S <br />/ <br />111 <br />476 <br />LJS <br />ei <br />-: <br />••+ <br />3.G <br />11- <br />:� <br />;L. <br />1(t6 <br />S <br />is) <br />5(a <br />60 <br />SS7 <br />3U <br />1 <br />:•: <br />S7I <br />711 <br />Y)3 <br />1J117 <br />93 <br />511 <br />7 <br />3W <br />SSL <br />`N <br />IU.31 <br />1173 <br />711 <br />)IJ <br />37U <br />IJ <br />17U <br />S13 <br />1 <br />31S <br />So <br />13 <br />1151 <br />1191 <br />712 <br />)W <br />3S7 <br />IItS <br />1/3 <br />1M <br />Y <br />111 <br />L1S <br />♦W <br />I)IN <br />I147 <br />J\6 <br />231 <br />34; <br />)+I <br />1310 <br />1LS <br />t0 <br />129 <br />1V <br />100 <br />1;(10 <br />21)) <br />7)1 <br />JN, <br />))1 <br />)7, <br />117 <br />111 <br />11 <br />111 <br />714 <br />it it <br />17 hi <br />11'13 <br />2N. <br />77• <br />313 <br />).; <br />395 <br />414 <br />•1 <br />163 <br />7/.0 <br />1'><I <br />�1 i) <br />.17i <br />41J <br />l, <br />