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C <br />A. mmine pump capadh'. <br />' Gravity Distribution <br />1. Minimum suggested is 600 gallons per hour (10 gpm) to stay ahead of <br />water use rate. <br />2. Maximum suggested for delivery to a drop box of a home system is 2,700 <br />gallons per hour (45 gpm) to prevent build-up of pressure in drop box. <br />Fmiure Distribution <br />3. a. Select number of perforated laterals 3 <br />b. Select perforation spacing a n. ft. <br />c. cubt 2 ft. from the rock layer length. <br />-2it. =j�,ft. <br />d. Determine the num} Df spaces between perforations. <br />Length perf. spsch ft. + ft. _ =Z spaces <br />e. spaces + 1 =_2L_ perforations/lateral <br />f. Multiply perforations per lateral by number o(' rats to <br />I <br />total number of perforations. <br />x a= _ Lc perforations. 1 13a a . <br />g• 10 X-,C*, gpm <br />SELECTED PUMP CAPACITY <br />e. Determine head requirements: <br />1. Elevation difference Wiveen pump and point of discharge. <br />- ('_ feet <br />2. If pumping to a pressure distribution system, add five feet for pressure <br />required at manifold <br />feet <br />3. Friction loss <br />a. Enter friction loss table with gpm and pipe diameter. <br />Read friction loss in feet per 100 feet from table. <br />F.L - 'aj,ja_ ft. ;,, )ft of pipe <br />b. Determine total pipe length from pump to discharge <br />point. Add 25 percent to pipe length for fitting <br />loss, or use a fitting loss chart. Equivalent pipe <br />length -1.25 times pipe length = <br />_ 1 x 1.25 - )S O feet <br />c. Calculate total friction loss by multiplying <br />friction loss in ft/100 ft by equivalent pipe length. <br />Total friction loss = ) • G x ) J +100 = _ V feet <br />4. Total head required is the stim of elevation di fervir.C, <br />special head requirements, and total friction loss. <br />(1) (2) (3c) <br />TOTAL , If ',I` feet <br />C. Pump sel:ction <br />1. A mimp must be selected to deliver at least gpm F. PI) <br />with at least _ ) S feet of total head (Step B). <br />DO PE VMTtttt/ OF A rEWOPATEa LATEPUiL <br />M fawr <br />d 40mook PAN go owl <br />ra.. <br />" tiusWW ^• Mw r . M.aN <br />r=r a..r <br />�• im N � t� (iaN <br />a . , IV�rw� tMu/ N <br />Cam <br />a.e LAW N �«d <br />TABU OF PERFORATION DISCHARGES IN CPW <br />Head PerfantimdVnt-wo OrKhea) <br />./M <br />,/, <br />149 <br />036 <br />0.74 <br />13 <br />Ob9 <br />0.90 <br />2.01; <br />0.90 <br />I D4 <br />23 <br />069 <br />1.17 <br />3.0 <br />a." <br />128 <br />4.0 <br />1.13 <br />1.47 <br />sA <br />126 <br />IAS <br />ache 1.0 foot of head for residential syst"M <br />bole 2A 6m of had be odrr eafabiishnenb <br />Pipe Length <br />I t <br />Point of DischF.......... j/010 �p <br />Elevation Diffemtce <br />Pump 0^ 4 tJ <br />F-18b <br />1.5 inch 2.0 inch 3.0 inch <br />9PM rVk%kMi.rr. i00n.tr%a <br />10 <br />.., 69 <br />0.20 <br />12 <br />0.96 <br />0.28 <br />14 <br />1.28 <br />0.38 <br />16 <br />1.63 <br />0.48 <br />18 <br />2.03 <br />0.60 <br />20 <br />2.47 <br />0.73 <br />0.11 <br />23 <br />3'3 <br />'.11 <br />0.16 <br />30 <br />5.A <br />1.55 <br />0.23 <br />35 <br />7.90 <br />1.06 <br />0.3P <br />40 <br />1107 <br />2.64 <br />0.39 <br />45 <br />14.73 <br />3.2r <br />0.43 <br />so <br />? 99 <br />0.`_8 <br />55 <br />4 76 <br />0.70 <br />60 <br />60 <br />0.82 <br />