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OSTP Mound Design Worksheet ;_��y� <br /> UNIVERSITY <br /> Minoesota Pollutbn >1% Slope OF MINNESOTA <br /> Control Agency �� <br /> 1• SYSTEM SIZING: Project ID: ���,pq,72 <br /> A.Uesfgn Flow(F(ow&SWl-1.A): 750 GPD TABLE IXa <br /> B.Soi/Loading Rnte(Row&Soil-3.C): 0.60 GPD/ft2 ��DING RAT6 FOR DETERMINING BOTTOM A850RPTION AREA <br /> AND ABSORPTION RATOS USWG PERCOLATION TE5T5 <br /> C.Depth ro Limi[inq Cond/tion: 1.0 ft ireaemaK�.w c fR(lvel A,A�2,B, <br /> i <br /> D.Perrent Lnnd Slope: 12.0 p; i ��� �°u0" � �� �� <br /> a,� nne <br /> E.Design Media Loading Rate: 1.2 GPD/ft2 , t�') "'tlO ��'1 �O <br /> F.Mound A6sorptton Rotto(Tabte IXa�: 2.00 ��o+ - � _ � <br /> G.Design Contour Loadirrg Rate: 12.0 GPD/ft �o.�to3 �.z � t.e � <br /> o+iosr�re.a�a o.s 2 , ,.s <br /> Table 1 aa r.o wrd <br /> MOUND COflTOUR LOADING RATES: B to t5 0.78 1.6 7 1.6 <br /> Moawrad 7onturo.dorivad Con(wr 18toJ0 0.8 2 O.7B 2 <br /> Por[Rato � mamd abspption ra[' lO�i� �•31 to 45 0.6 2.4 0.T8 2 <br /> Rato: <br /> !46 to 60 0.16 2.6 0.8 2.6 <br /> z50nWi 1.0.1.3.1.0.2.�.2b .12 <br /> '�B�to 720 . 6 0.3 6.3 <br /> 61-I20mpi 00. SA _11 .at20 - " ' " <br /> _�io nipf- -s.o' �b' Systems wkh these vatues are na Type I syscems. Contaur LoadMg Rate(Unear <br /> loaAing rate)is a recommended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A.Calcutate Requfred Dlspersai Bed Area:Destgn F(ow(i.A)+Design Media Loading Ra[e(1.E)-ft1 <br /> If a larger dispersal medta area 750 GPD a 1.20 GPD/ft� - 625 ftz <br /> is desired,enter size: � <br /> �ft� <br /> B.Cakulate Disperw!BedWidth:Contour Loading Raie (t.G)+Design A{edlo Loading Rate(1.E)=Bed Width <br /> 12.0 ft t 1.2 gpd/fc� = 10 ft <br /> C.Calculate Disperwl Bed Lenqth:Wsperw/Bed Area(2.A)=Bed Wid[h(2.8)=Bed Cength <br /> 625 ft= - 10 ft = 63 ft <br /> D.Select Dispersal Media: rOck <br /> E. If using a registered product,enter[he Component Length: �in= 12 - �ft <br /> F.If using a reglstered product,enter the Componenc Width: �In s 12 - �ft <br /> G.Number o(Componenu per Row=Bed Lengtfi(2.C)divlded by Compnnent length(4.J)(Round up) <br /> � ft ' � ft- �componenu/row <br /> H.Num6er of Rows=Bed Width (2.8)dtvided by Component Width(4.K)(Round up) Note:CLR o(f0.3 <br /> AdJus[Cwi[our Loadin Rate on Desi Summa gal//t rew(ts in 9(oot <br /> g gn ry page unttt[his number is a whole number ��� <br /> � h+ � ft� � rows <br /> �, Toto!Number of Components a Number of Cornponen[s per Row X Number o/Rows <br /> � X � �components <br />