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Mound Design Worksheet (FUTURE) <br /> Ali boxed rectangles must be entered,the rest will be ca�ulated. <br /> A. FLOW k 1: Fsl�naled Sewape Aans in Galars Der Da! <br /> Estimated 750 gpd(see figure A-1) �� �� �h ���� �ry <br /> or measured 0 x 1.5(safety factor)= 0 gpd 2 �pp 225 �80 60�6 <br /> B. SEPTIC TANK LIQUID VOLUMES 3 �i0 300 218 of the <br /> Septic tank capacity 2300 gallons(see figure G1) 4 b00 375 256 val,es <br /> 5 150 450 294 in the <br /> C. SOILS(Site evaluation data) e 900 525 332 qa�I, <br /> 1. Depth to restricting layer= 1.7 feet > >� � 370 I,aul <br /> 8 1200 615 408 cckgrr�a, <br /> 2. Depth of percolation tests= inches <br /> 3. Texture LOAM <br /> 4. Soil loading rate(see Figure D-33 0.6 gpd/ft� <br /> Percolation rate 4 MPI <br /> 5. %Land Slope 9 °� D-33: Absorptbn N IrMh Sising Table <br /> Porcolaroo Rate Lond�ag Rate <br /> in Minan per Swl Texture GelloM Absorywon <br /> C-1: Se le Tank C ifks 11n allons� �"`" �"°ay'pe� R�'° <br /> hlPl asve foa <br /> (,)qUtd Cd�Clt� Faaer�lun S Cavse Sand I.20 l 00 <br /> Number of :��ticumwn laywd Irquid capacity with �,1����� "��;y�;a <br /> Br�oams Capac�t}� garbagc d�s�osal lifi inside F�ne5a.Lnd� _ <br /> 2urless �50 I1�5 ib�oso o.ao �oo <br /> 1 i()() 31 W�5 �i1t Loem 0 SO 40 <br /> 3 or� I OfiO 1�00 2W1) +6,0 60 �r.i�. o.as z 6� <br /> 5 cx b 150G 2I.50 3U1)I) si��•c.tay t.o�m <br /> ",8 or 9 �004 3000 <br /> 61[0 120 S�Jq•t:]�y 0.?� 5 00 <br /> Sandy Clay' <br /> CI - <br /> �lower thn 12 ' <br /> 'SysYnn deaipM for fher voit�mua E�uArr a prfumaec� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer: Item A x 0.83= <br /> 750 gpd x 0.83 ft�gpd= 630.0 ft <br /> 2. Determine rock layer width =0.83 ft/gpd x Linear Loadin Rate(LLR)(see LLR chart) <br /> 0.83 ft�/gpd X 12 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rock layer=area divided by width= <br /> 630 ft� I 10 feet= 63.0 feet <br /> E. ROCK VOLUME <br /> 1. Mul6ply rock area by rock depth to get cubic feet of rock <br /> 630 X 1 ft= 630.0 ft3 <br /> 2. Divide ft tiy 27 ft3lyd3 to get cubic yards <br /> 630.0 ft/ 27 = 23.3 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 23.3 yd3 X 1.4 tonlyd3 = 32.7 tons <br />