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septic design-2001
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515 Kokesh Farm Road - 31-118-23-14-0009
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septic design-2001
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Last modified
8/22/2023 4:29:27 PM
Creation date
4/12/2017 3:05:31 PM
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x Address Old
House Number
515
Street Name
Kokesh Farm
Street Type
Road
Address
515 Kokesh Farm Road
Document Type
Septic
PIN
3111823140009
Supplemental fields
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MOUND DESIGN WORKSHEET <br /> (For Flaws up to 1200 gpd) <br /> A. FLOW Esumated Sewaec Flows m Gallun= <br /> r dl D�r day <br /> Estimated �d N��, �,,�, �„ ��o � <br /> or measured x 1.5 = �,�d �'°°^� N <br /> '- �oo zs I i� <br /> ' boo �30is� zsa ' °�� <br /> B. SEP1'IC TANK LIQUID VOLUMES ` " 5 ��o a�o �„ •y� <br /> /�D gallons /S�N� ��tt�Tq.�.� : /047� � �0 60 ;o Tm�� ' <br /> ''_ _/ 8 1200 675 apg 0 O1 <br /> /D�O 6'fiG��x/ Ziva TA.vi� �`�/(J W mrtc <br /> C_ SOILS (refer to site evaluation) <br /> 1. Depth to restrictin la er - Z Se 'cTaakCa ,e,,;�,;, ,,,,�5, <br /> g Y - inches feet Lqwdcapx�;; <br /> 2. Depth of rC�l t1�Il fe$t$ _ _ � � inches �umCcroi Flmimuml�qud t�qudnpucxyw�N Wi�hd�sposala <br /> � Bedroo:ns Cap�eey tarb�ge drsposa! lift insde <br /> 3. Texture Percolation rate �o�kss ,w ;,,; <br /> S p/ � mPl )a� �pp� �cQ,p Ii00 <br /> 4. Land slope__ o ;ab ,� �,� �000 <br /> �.aa9 � � � <br /> woo <br /> D. ROCK LAYER DIMENSIO�� <br /> 1. Multiply flow rate by to o tain required area of rock layer: A x 0 83b Mound LLR <br /> �_gpd x ' sq. ft./ d - Perc Rate LLR <br /> 2. Determine width of rock layer = 0.83 sq.�ftP./gpd�near Loading Rate (LLR) �120 MPI < 12 <br /> �sq. ft/gpd x� = 75'� ft >120 MPI 5 6 <br /> 3. Length of rock layer = area = width = <br /> jl. - �_ 4;e:A'�"os�.. P'!'07�. �����:,-�:l'm:�Y'(e.o0. �e:eQ •'e.6�n6.��(Q • <br /> sq. ft. = -�O _ ft. Q.. .:.,,.p��. ��.b/��:.;�..;: <br /> . oia:�C4'Tb.►�f.�.7.��p�'A� p, ' �".� .' �:. . ..... <br /> . QadQo�'�l;�t�e:�..�r..�:aa:9a� :. � ::.. :.. <br /> ..a.:eb eo�tinve'iQ:r. ib< _..,;. - <br /> Width 1�ft v�.�`.�Q..o:�. �;�: <br /> .O .e�.�s.�e-e :e> v.Y.' <br /> <120mpi <10' Length �'S ft <br /> E. ROCK VOLUME >120mpi <S' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. ft. x � ft. _ <br /> 7� cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. = 27=�$cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;3�cu. yd. x 1.4 ton/ <br /> F. ABSORPTION WIDTH <br /> 1. Percolation rate in to 12 inches of soil is �_ mpi Absorplion�Yidlh Sizing Tablc <br /> Texture � /�// ��0VU0"R��� Gallona Rauoo/ <br /> �tinaes per Ineh Soi�Tca�ure �,a�.�a, MsorTMion wiAU <br /> �I� (A1PI) <br /> squa¢foo� io Rock l�yc� <br /> WdU� <br /> 2. Select allowable soil loading rate from table; Fu""�°' `""`S'"° ��° '°° <br /> 0.1�0 5 MeCium AnJ 1.?0 I.DO <br /> �.(� p'7-)d/f t� Firc Sa�d <br /> 0.1�0 5 0.60 2.00 <br /> c�r 6to1S SaMyLoa,n 0J9 LS_ <br /> I6 w 70 Laun 0.60 I.W <br /> 71�0�5 SikLoam 0.50 I.10 <br /> 16 w 60 Clay Loam(Cl OA S 2.67 <br /> 3. Calculate absorption width ratio by dividing rock layer 5.a,« <br /> SaMr CL <br /> oading rate of 1.20 gpd/ft2 by allowable soii loading rate; s�o�°���°,� �;;; o:Zo 6:� <br /> 1.20 gpd/ftz = r�•?9 gPd/ftz = ..SZ, . <br /> 4. Multiply absorption width ratio by rock layer width to get <br /> required absorption width; <br /> �SZ X _.L� ft = S•z�€t <br />
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