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r.�. <br /> ��UMf SELGC�f10N ('ROC[iUURf: <br /> A. �ctc[minc pumE� capacity: <br /> Gravily Distribution <br /> 1. Minimum suggcstcd is 20 g�>�n <br /> 2. Maximum suggcstcd is 45 gPm <br /> ['�essurc Oistibution <br /> 3. a Scicct number o(perforated latcrals Pcrio�.c�on��sch,�g�S;�,GrM <br /> b. Select perforacion SPaCing = __ fcct. tlead Perfo�ationdiame�er <br /> c. Subtract 2 ft. (rc�rn Uic rock layc�Ic�gth. �re� �nches <br /> rt..�.�.n,�<Km' 2 fl =_ fect. 7/l2 1/4 <br /> d. Determine the number of spaces between perforations. �.o+ oSb o.�a <br /> Le�gth pe�(. spa.:ing = ____ (t. � _ ft. = sPaces � t.s 0.69 o.qa <br /> 2.06 0.80 �pq <br /> e. sPaces + t = perforatians/lateral <br /> f. Multiply pecforations per latera!by numbcr of latecals to '�1se l 0 foot single I�ornes <br /> get tota! number of per(oratio�s. x - perforations_ b t►se 2.0(eee for a�y�h;�s e�u <br /> zr-.T � � .. - <br /> g. �m z u�a =--.-gPm. <br /> SELECT[D PUMP CAPAC(TY�3v��� gpm <br /> E3. Dcterminc head requireme�ts: �•�«<•��,�����•�. <br /> 1. Elevation difference between pump and point of discharge. ��•�•���� <br /> �Q fcet to�.i���i��6a. <br /> 2. 1f pumping to a pressure distribution system, five feet for pressure % <br /> ��_ <br /> required at manifold i(gra�•it s stem, zero. �9 <br /> �__ fccl t��ci t:i.,•.��o�u,u�,.•M�- <br /> F,`` V � � <br /> ; �'CICl10(1 �Oj$ ; .._ .. I <br /> a. Enter friction loss table with gpm and pipe diamcter. � • /p�!� <br /> Read riction lass in(eet per 100 feet from table(F-14). _ <br /> -••.... ... . . . .. .... ..... ... <br /> F.L. _ ��p._ (t./100 ft of pipc <br /> b. Determirie lota!pipc length (rom pump to discha�ge Friction Loss in Plastic Pipe <br /> point. Estimate by adding 2S peccent to pipe length fonfitting Nominal <br /> loss,or use a fitting loss chart(F-15 feet). pipe dia. <br /> Equivalent pipe length- 1.25 times pipe length= Flow Rate /,'�- ) <br /> ��_X 1.25 = zr3 feet gpm 1.5" ��c,/ 3_ <br /> c. Calculate total friction loss by multiplying <br /> friction loss in[t/100 ft by equivalent pipe length. 20 2.47 0.73 0.11 <br /> Total friction loss = �3 x �iL. 7ib +lpp-�_feet ZS 3.73 1_il 0.16 <br /> 4. Total head required is the sum of elevation difference, � 5.23 1.55 0.23 <br /> 35 6.96 2.06 030 <br /> special head requirements,and total friction loss. 40 8.91 2.64 0.39 <br /> 45 11.07 3.28 0.48 <br /> --�_ + _�_ + �d SO 13.46 /3� 0.58 <br /> (I) (2) (3c) SS ��. OJO <br /> 60 5.60 0.82 <br /> � 6S 6_48 0.95 <br /> 'fOTAL HGAD �� fect �0 �•44 1-09 <br /> C. ['ump. scicctio� <br /> 1. A pum�� must be selected to deliver at least <br /> _��gpm (S.tep:ll) with.at least �,� feet o.f_total head(Step;.�)... . <br /> .... _,:... , , <br /> -- ::_.:" � - <br />