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• ('ItESSURf: p(ST'[ZIf3U'I'ION SYS"I'�M c�+o rcRrortnrux� or n r•cRr�,����u � ���«,,.
<br /> i-c,a�. ce..,
<br /> l. Scicct numt�er of pc�(o�ated latcrals _� _ '`--`—
<br /> �oo.e�� -�`
<br /> � '
<br /> �. , ____ , --_
<br /> 2- Select perforation spacing = __ •5 _ fect. � �•a^�S°^��r« ;�,',;,�������.�„� �,,,,� ,,, .
<br /> •ein«a,��"O�a. . o,«-..
<br /> �^oa�..�„
<br /> �`� ... ao�' •-rarwo�.a,an�_e ��v..��.,...
<br /> 3. Since perforations sl�ould not be placed closer ttian l ft. to � _._ ""' `'° ��< <�o
<br /> �/�'Plut �\�'•
<br /> ttie edge of thc rock laye� (scc diagram), subtract 2 (t. f�on� �'��F���R . ' � 4� `"" 'z��^ ' �.
<br /> . . �•^ .r ao�. �a«.
<br /> the rock layer lcngth. ''•«�a,; '
<br /> C�.ae SonE lope. Bo��om e�alxo�ra or
<br /> <ro�
<br /> ��� �
<br /> R«k�.,.«�rngu, ' f t. _ �is�• S f e e t. -a,,_�s,,, P„a.�,K`�..�`--�..a
<br /> Bafw�Pbctp �,b La��r
<br /> 4. Determine the number of spaces between perforations. �"e',,,��'°'•�°^��—
<br /> � v��.,,.�<�P_�
<br /> Divide the lengtl� above by per(oration spacing and round �` �+�.,., - -�--
<br /> do�vn to nearest cvhole nurtiber. "`"' ' �^
<br /> 1.Oa 0.56 0.74
<br /> Len�th perf. spacing =�2�Sft. :�•Sft. _ �,� spaces 2-0b �-80 �_��q
<br /> �3� �2� a.Usc for single fartuly homcs
<br /> 5. f�lumber of perforations is equal to one plus the number c�f b Uscforallolh�rappl�cat�ons
<br /> perforation spaces .
<br /> �G� Maximum numbcr of quartcr inch perforatio�u,�
<br /> _ spaces + 1 = �_ Perforations/lateral lateral togvamaneee c 1p%discharge variativ:+
<br /> f crforation
<br /> G M��Itiply Nerforations per lateral by number of laterals tc� SPre��g (� ly 2
<br /> get total number of perforations. 2 -- --
<br /> 2.5 14 18 28
<br /> `�,;,t X �— _ �.� perforations. 3.O I3 17 2(�
<br /> �"h,�""'' 3.3 12 16 25
<br /> 7. Determine required flow rate by multiplying - 4.� I1 15 23
<br /> number of perforations by flow per perforation 5.0 �� 14 22
<br /> � �/—�--� ♦ �. ��N'«Ol0 lOCA1LD 4f CW O� �'K1R/1C 04fA�W�W {YSTIr
<br /> P«is x 6pm/pct( —�p
<br /> 8. [f laterals arc connected to he er pipe as shown on upper �
<br /> :
<br /> examp e, sel t minimum re ire teral diameter;enter � �
<br /> �
<br /> table with p o�ation spacing a mber of perforations �,,.�"' `_"
<br /> per latera Se �t minimu� iameter o •''�
<br /> perfora ed lateral = ___ inclies. \�
<br /> U�0.rt✓IfAIM�fP I'i(Y�[�LL�iY
<br /> ^'�+�iK lfw�./�C.�w'e'/o
<br /> (�,() r�(
<br /> ` .�.�..�.�r.<« f �
<br /> 9. (f perforated (ateral system is attached to manifold pipe riear- 1= �''Kti .�''`�,M, /��
<br /> the center, (owec diagram, perforated lateral length and K�;,�;�.„�., -
<br /> number o( perforations per lateral will be approximately o►ie `� " �'-��� �
<br /> I�alf of that in step 8. Usin� tlicsc valu s, select minimum ,_� � �,,�'�
<br /> dian�e�er (c�r �:�er(ora(ed lale��il = --t-�` �nclies. ,, �,�.."'' ..`."..
<br /> � ��
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