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septic design-2005
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Last modified
8/22/2023 4:42:02 PM
Creation date
4/12/2017 9:09:53 AM
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x Address Old
House Number
140
Street Name
Kintyre
Street Type
Lane
Address
140 Kintyre Lane
Document Type
Septic
PIN
3211823430019
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' o�� Job#� <br /> asw.rss <br /> Tw�wrMart <br /> P�eoswwrr <br /> Univers' of Minnesota Mound Design Worksheet S�e B <br /> �r�te�than 19G Slopes <br /> a �ow <br /> E�� 750 9Pd(see figure A-1) <br /> or measured x 1.5(safety factor)= U 9Pd <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> ��k�ty �p g�lons(see figure G1) <br /> N�ur�ber d tanks/compa�trnenis 0 <br /> Eflh�ent Filbar (yesh�o) Yes <br /> C-1 Sepfic Tank C�adly�Gallons <br /> Number of Nfininwm Capaaty with Capacity with <br /> Bedrooms C�aahr Garb.Disp. Disp.and Lift <br /> 2 or less � � � ��� :� 1125 �;' ��� � --: <br /> � <br /> 3 or 4 � � , ; 1500 ; �*�. <br /> 5 or 6 ���T � 7150 �: '�'~' <br /> > <br /> , <br /> 7 8or9 �I:;��`" t 3000 '����. <br /> � <br /> C. SOILS(Site evalu�ior►dffia) <br /> 1. Depth to restricting layer- 1.8 feet <br /> 2. Depth a�per�daaon tests= 12 inches <br /> 3. Texture � <br /> 4. Shc loadng tate(see F'�ure D-33) 0.60 9P�� <br /> p�,pd��, 6 MPI <br /> 5. %Land Sbpe 9.0 % <br /> D. ROCK LAYER DIMENSbNS <br /> 1. Mutdply average design flow{A)by 0.83 to obtain required area of rodc laye.c:ltem A x 0.83= <br /> 750 gpd x 0.83 ft/gpd= 630 ft� <br /> 2. Detertnine rndc layer width =0.83 ft`Igpd x Linear Loadng Rate(LLR)(see LLR chart <br /> 0.83 ft Igpd x 12.00 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <� <br /> 3. Length of rodc►ayer=area divided by width= <br /> 630.0 ft! 10.0 feet= 63.0 ft <br /> E. ROCK VOLUME <br /> 1. Multiply rodc area by rodc depth to get cubic feet of rodc <br /> 630.0 X 1.0 ft= 630.0 ft <br /> 2. Divide ft3 by 27 ft31yd3 to get cubic yards <br /> 630.0 ft3 / 27 = 23.3 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 23.3 yd3 X 1.4 toNyd3 = 32.7 tons <br /> Page 1 of 5 <br />
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