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i <br /> ' ' � � <br /> � ' PRESSURE DISTRIBUTION SYST�M Geotextile fabric <br /> - I <br /> � : ' <br /> 1. Select number of perforated laterals '� i arter inch erForations aced�3' �,. <br /> � � , � <br /> 2. Select perforation spacing= 3 r ft � s'of.�oc�` <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be placed closer th 1 foot to Perf Spacing 1.5�-s' <br /> the edge of the rock layer(see diagram),subtract feet from <br /> the rock layer length. � E-4: Maximum aqowable nu�of 1/4inch perfor� <br /> per laterd to guarontee<l OX c�sch�ge variation <br /> a c ayer� -2 ft =�ft <br /> I PefIOf0�W1 <br /> � ��� <br /> 4. Determine the number of spaces between perfora 'ons. f� �� �,��h 1.5 inch 2.0�h <br /> Divide the length(3)by perforation spacing(2)a�d round <br /> down to nearest whole number. � y.5 8 14 18 28 <br /> Perforation spacing= �1� ft T�ft=�spaces 3.0 8 13 U 26 <br /> � 3.3 7 12 16 25 <br /> 5. Number of perforations is equal to one plus the n�.unber of 4.0 7 11 15 23 <br /> perforation spaces(4). Cherk figure E-4 to assure thq number of <br /> perforations per lateral guarantees <IO%dischnrge va�iation. 5.0 6 10 14 22 <br /> ��spaces+ 1 = l 7 perforations/lateral E-6: Pertorc�tion Discharge in gpm <br /> 6. A. Total number of perforaHons= perforations p�r lateral(5) perforation diometer <br /> times number of laterals (1) � head jnches <br /> (feet) 3/16 7/32 1/4 <br /> �perfs/lat x 3 lat=�S,L perfo�rations �,Oa 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. � 2,Ob 0.59 0.80 1.04 <br /> Should be 6-10 sqft/perf. Does not apply to at grac�es. <br /> Rock bed area= rock width (ft) x rock length(ft) 5.0 0.94 1.26 1.65 <br /> �ft x ,S� ft= s o a sqft � a Use 1.0 foOt fOr single-fomiy homes. <br /> Square foot per perforaHon=Rock bed area +npmber of perfs (6) b Use 2.0 feet tor an i e��. <br /> t�J sqft=�_perfs= •`4� sqft/p�erf <br /> MGI�fOID lOCA7E0 AT END OF PNE53URE dSTRIBU�WN SKTEM <br /> 7. Deternune required flow rate by multiplying the t� tal number of <br /> perforations(6A) by flow per perforation(see figu e E-6) ,.�,. <br /> �1 perfs x ��gpm/perfs= �� '""""' <br /> �gpm <br /> 8. If laterals are connected to header pipe as shown o�n upper �,�;�,'''�j� <br /> example,to select minimum required lateral diameter;enter ,.� <br /> �� ���� <br /> figure E-4 with perforation spacing (2)and numbe�r of perforations ��`"°M <br /> p�r lateral(5) �elect m.inimu�n diameter foz ' � <br /> ��, ; 4TOUT Of/EMOIYTED PV[t,�TEP�1.5 rOR <br /> perforated lateral= �?�ulches. � "�w°'^�„�»N.�°,° <br /> .d.o..,��...K..r <br /> 9. If perforated lateral system is attached to manifold�pipe near E��,,,a,,,�� „� <br /> the center,lower diagram,perforated lateral leng�j (3) and � �=`� ��"'�� <br /> number of erforations er lateral 5 will be a rbximatel one R �..��a � <br /> P P � ) PP Y �,�.� <br /> half of that in step 8. Using these values,select 'm�imum '°�� - _ ,_���� <br /> diameter for per forate d latera l= ----- in c hes. I � ,� <br /> � �,.,� <br /> I d �� � <br /> , ��� <br /> ( <br /> I hereby certify that I hav�ompleted this work in accordanc with applicable ordinances, rules and laws. <br /> �i `�'"� ��•�',� `---•—_. si na r ��1 # �� � <br /> ( s tu e> (Iuense ) 13 (late) <br /> � <br />