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2009-00589 - new septic
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3445 High Lane - 05-117-23-12-0025
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2009-00589 - new septic
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Last modified
8/22/2023 5:16:18 PM
Creation date
1/26/2017 2:46:52 PM
Metadata
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Template:
x Address Old
House Number
3445
Street Name
High
Street Type
Lane
Address
3445 High La
Document Type
Septic
PIN
0511723120025
Supplemental fields
ProcessedPID
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l�nivewnoFM�KNcsittw � <br /> Pressure Distribution Design <br /> Minnesota Pollution = ��� � <br /> Control Agency Worksheet .����*3�• <br /> Geote#ile <br /> 1. Select Number of Perforoted Laterals : 3 �����y`°�o�oqm� Minimum 6q;o6'° a'� " <br /> !. perforations spaced 3'apart�q 2'of rockc� or.�� <br /> (2-3 foot spacing) ?�+o�o <br /> 2. Select Perforation Spacing: 3.0 ft � o_ tz" <br /> � o �._ � o��Ya� <br /> Note:Must use 2 feet for media filters ���� � � 9°of rak ���a�� <br /> o �a���a�a� ��� o� a <br /> 3. Select Perforation Diometer Size 1/4 1f1Ch Perforation sizin /a'ro'h' <br /> 9� <br /> Perforation s aun :2'ta 3' <br /> 4. Length of Laterols =Media Bed Length-2 Feet. Perforation can not be doser then 1 foot from edge. <br /> 38 - 2ft = 36 ft <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Loterols (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 36 ft .- �ft = 12 Spaces <br /> 6. Number of Perforotions per Latera( is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = 12 Spaces + 1 = �3 Perfs. Per Lateral <br /> Check Tab(e/to ensure that the number of perforations per tateral guarantees less than a 10%discharge variation. <br /> �• Tota(Number of Perforations equals the Number of Perforations per Latera( (Line 6)multiplied by the Number of <br /> Perforated Laterols (Line 1). <br /> 13 Perf. Per Lateral X �Number of Perf. Laterals = 39 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended value is 4-f0 ft2 per perforation. Tat�e ui <br /> Does not upply to At-Grades rerforation Discharge(c,W� <br /> Bed Area = Bed Width (ft)X Bed Length (ft) Perforation Diameter <br /> Head(ft) � a � , <br /> 10 ft X 3$ ft = 380 ftZ �• i,b i33 �� <br /> �,p' �.18 0.41 0.56 0.74 <br /> Z,p° 0.26 0.59 0.80 1.04 <br /> Square Foot per Perforation =Bed Area divided by the Totol Number of Perforations (Line 7). 5• o.a� 0.93 �.2e t.es <br /> a:Use 1.0 fw d�vetlir�s using 114 inch or 3/16 inch <br /> hdes. <br /> 380 ftZ - 39 perforations - 9.74 ft2/perforations b:Use 2.0 fa dwellirqs using 1!8 iixh hdes;«,t« <br /> other establishments using 1/4 inch a 3/16 inch <br /> hdes. <br /> 9. Select Minimum Average Heod: 1.0 ft c:Use SA fw othFx establishments�sing 1l81rxh <br /> perfaatia�and media fil[ers. <br /> 10. Select Perforation Dischorge (GPM)based on Table III: 0.74 GPM per Perforation <br /> 11• Determine required Ftow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> 39 Perforations X 0.74 GPM per Perforafion = 29 GPM <br /> 12. Select Type of Manifold Connection (End or Center}: �end ❑center <br />
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