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u,.���ws�..w u�<..�n., <br /> � , Non-Level Pressure Distribution Design - -- <br /> Minnesota Poliution WOr'kSh@et - <br /> Controi A enc <br /> 6. Determine the F(ow Rate per Hole <br /> Select a Perforation Diameter and the corresponding Q, _ � / .6 5 cd 2 � <br /> gallons per minute from Tabte i, interpolating as needed. c=0.60;d=perforation diameter; h=pressure head <br /> or Calcutate Perforation Discharge(�in GPM: <br /> Lat 1 Pressure Head �.� ft Perforation Diameter 1/4 = 0.74 GPM Highest <br /> Lat 2 Pressure Head 2.5 ft Perforation Diameter 1/4 = 1.�7 GPM <br /> Lat 3 Pressure Head �ft Perforation Diameter� � GPM <br /> Lat 4 Pressure Head �ft Perforation Diameter� � GPM <br /> Lat 5 Pressure Head � ft Perforation Diameter� � GPM Lowest <br /> 7. Catculate Ftow in Galtons Per Minute for Lateral 1 Perforation Discharge(GPM) <br /> Perforation Diameter <br /> A. Select Perforation Spacing: 2,� feet Head(ft) ,�e =/,6 '/,x '/, <br /> B. Length of Laterais =Length of STA(Line 1)-2 Feet 1.0' 0.18 0.41 0.56 0.74 <br /> 1.5 0.22 0.51 0.69 0.9 <br /> 3 8 -2 ft= 3 6 2.0° 0.26 0.59 0.80 1.04 <br /> 2.5 0.29 0.65 0.89 1.17 <br /> 3.0 0.32 0.72 0.98 1.28 <br /> �• Number of Perforation Spoces =Divide the Length of Laterat 1 (7.6)by the 4.0 0.37 0.83 1.13 1.47 <br /> Perforation Spacing(Line 10)and round down to the nearest whole number. 5.0 0.41 0.93 1.26 1.65 <br /> Check Table II to ensure the maximum number of perforations is not exceeded. a:Use 1.o for dwetlings using 1/4 inch or 3/76 inch <br /> 36 fci � � nd�. <br /> 2,0 ft= �$ Spaces b:Use 2.0 for dwellings using 1/8 inch holes;�,ro� <br /> other establishments using 1/4 i�ch or 3/16 inch <br /> D. Select Type of Manifo(d Connection (End or Center): �E� ��,� hdes. <br /> E. Number of Perforations=Number of Perforation Spaces(Line 11)+ 1. c: Use 5.0 for other establishments usi�g 1/8 inch <br /> perforations and media filters. <br /> 18 Spaces+, = 19 <br /> F. Flow Rate for Lateral 1 =Number of Perforations X Fiow Rate Per Ho(e for Latera( 1 <br /> 19 x 0.74 = 14.0 GPM for Lateral 1 <br /> 8. Calculate the Galtons Per Mi�ute Per Foot for Lateral 1. This value wilt then be used to make <br /> sure that the gallons per minute per foot is equivalent in each lateral <br /> Gatlons Per Length= Flow Rate for Lateral 1 divided by Length of Laterat 1 <br /> 14.0 = 36 = 0.39 GPM/Foot <br /> Masi^au^k N�mber�f Pe-f�atia=vs F'e�Laterai to�.uar�r.te?�1�L�=->charge`.'�ra^a+� <br /> ',i���Fert�ra;-cns i'."2 i�•_�Fe-fcrrdo-Ts <br /> Pa-fcr�!-on SFecng{Fe?ti �F?�ia^e'_x�1-rchesi Ferfcraci��SFa_in� Fip�Ra^+xter i'ncF?s'.� <br /> �•_ 11: Z 3 (�eetl ! _ �t4 2 s <br /> � !6 13 1Q 34 60 2 7� 9d 2! 3? 6E <br /> '�� 8 12 i5 26 5� �.�= 7C`� i� 20 3i t_.-i <br /> � S '�2 16 25 Si 3 g 34 19 ;�.i 6C� <br /> 3'16"rch aer'orations 1 '8 Int�Fe-frra'-n�s <br /> Pig?C�ia^e!x'.I�chesl Pe-frrr�zia�SFacins Pipp Ra^eter f1ncF±es` <br /> Fe-fcra:•o�SFacng IFee:t ' <br /> t 1�_ �'•` Z 3 (`ee`.S 4 *i_ 1�~ 2 ' <br /> 2 i2 1P �6 4b E; 2 �; 33 4-1 74 1�9 <br /> 2i". 12 17 2-? 4+� 80 2'�`. Z�� _i� 4? 6� 13°: <br /> � l2 t+� i2 37 7s } ZG 24 38 54 12°� <br />