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2007-12-14 11:42 MNVALLEY 5072483501 » 952 474 4193 P 7116 <br /> 1.5 MOUND SIOPE WIDTH 8 LENGTH(Greaterthan 1Yo) <br /> t. Dvwn5lope ab5orp6on widih=ab5�rption width minus rock layer widih Clay <br /> 20 feet - 10 feet= 10 feet <br /> 2. Calcutate mound size <br /> UPSIOPE <br /> a.Determine depth of dean sand at upalope edge of rodc layer=3 feet minus distance to restncting laye�(C1) <br /> 3 ft • 2 ft= 1 fest <br /> b.Mound heighl at 1he upsiope edge of rock layer=depth of dean sand for aeparation(G2a) <br /> at upslope edge plus depth of rodc layer(t foot)to depth of cover(1 foot) <br /> 1 R i 1 ft+1 ft= 3 feet <br /> c.Upslope berm muldplier based ati Iand�Io see figwe a34) <br /> Select berm multiplier of 2,94 <br /> d.Upslope aridth=berm mul6plier(G2c)6mes upslope mound height(GZb): <br /> 2.94 x 3 ft = B.B feet <br /> DOWNSLOPE <br /> e.Drop in elevation=rock larer width(02)Gmes pe►cent lend5lope(C5)I 100 <br /> 10 ft x 9 96 !100= 0.9 feet <br /> f.Downslope mound height=depth of dean sand tor sfope difference(G2e) <br /> at dow�slope rock edge plus the mound height at the upslope edge ol rodc layer(2b) <br /> 0.90 ft + 3 ft= 3.9 feet <br /> g.Downslope barm multipiier based on percent land slope(see Figure d-34) 5.18 <br /> h.Downslope width=downslope muttiplier(G2g)times downslope mound heighl(G2� <br /> 5.18 x 3.9 - 20.2 teet <br /> i.Select greater of G1 and G2h as the downsbpe width 26.2 feet <br /> j.Total mound width i�the sum of upslope�G2d)widU►plus rock iayer width(02)p►us downslope width(G2ij <br /> 8.8 ft• 14.0 ft+ 20.2 ft= 39.0 feet <br /> k.Totel mound length ia the sum of up�lopt width(G2d)plus rodc layer length(D3) <br /> plus upslope width(G2d} <br /> 20.2 ft * 62.3 ft+ 20.2 ft= 102.7 teet <br /> Final Dimensions sl e�1% 39.0 ft x 102.7 fl <br /> 1 hereby ce+tify q�et 1 have completed this worlc in eccordance with all applicable ordinences,n,1es and{ews <br /> Rondy Melkow DRP Reg�5327 <br /> Mn Valley Excavating Lic tl2085 12112/2007 <br /> Page Z of 6 <br />