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2007-12-14 11:42 MfVVALLEY 5072483501 » 952 474 4193 P 6/16 <br /> � Mound Design Worksheet (Far flows up to 1200 gpd) <br /> All boxed►ectangles mus!be enfered,the rest wiHbe calculated. <br /> A. f L�W <br /> EsGmated 750 gpd(see fx�ure A-U <br /> or measured x 1.5(safety tactor)= 0 gpd <br /> 8. SEPTlC TANK LlQU1D VOLUMES <br /> 5epbc ta�k capacity 2250 gallons fs�f�9ure G1) <br /> i� a spaci �n on� <br /> Number of Minimum Capacity with Capacity with <br /> Bedrooms Capacity Garb.Disp. Disp.and Lift <br /> 2 or less 750 1125 150Q <br /> 3 or4 1000 150Q 2000 <br /> 5 or 6 1500 2250 3000 <br /> 7,8 or 9 2000 3000 A� <br /> C. SOILS(Site evaluation data) <br /> 1, Depth to resvlctlng layer- 2 ��� <br /> 2. depth of percoletion tesls= 12 inches <br /> 3. Taxture loem <br /> 4, Soil foading rate(see F'gure D-33) 0.6 gpdt t� <br /> Parcolation rate 9 �►P� <br /> 5. °�Land Slope 9 °b <br /> D. ROCK LAYER DlMENSIONS <br /> 1. MuIGply average design 8aw(A)by D.63 m obtain required area of rodc layer:Item A x 0.83= <br /> 750 gpd x 0.63 ftvgpd= 622.5 ft' <br /> 2. Determine rocic layer w+dth =0.83 ft lgpd x Linear Loadin Rate LLRy(see LLR chart) <br /> 4.83 ftZlgpd x 12 - 10.0 ft <br /> ��� <br /> LlR Chart <br /> Peric Rale LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Lenglh o1 rock leyer=erea divided by widtlt= <br /> 622.5 ft2 / 10 feet= 62.3 feet <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by roc�Cc deptfi b get cubic feet oF rock <br /> 622.5 X 1.2 ft= 747.0 ft� <br /> 2, Divide ft�by 2T ft3/yd3 ta get cubic yatds <br /> 747.0 ft3 1 27 = 27.7 ydz <br /> 3. MuNip�y cubic yerds by 1.4 to get wei�t of rock in tons; <br /> 27.7 yd' X 1.4 tonlyd� = 38.7 tons <br /> F. ABSORPTION WiDTH <br /> 1. Absorp6on width els absorption ratio(see Fipure D-33)6mes rock layer width <br /> 2 x 10.0 ft = 20.0 ft <br /> Page 1 of 6 <br />