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2010-01069 - new mound septic
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2720 Fox Street - 04-117-23-42-0004
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2010-01069 - new mound septic
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Last modified
8/22/2023 5:13:38 PM
Creation date
11/14/2016 2:06:31 PM
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x Address Old
House Number
2720
Street Name
Fox
Street Type
Street
Address
2720 Fox St
Document Type
Septic
PIN
0411723420004
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5. S stem Type Distribution Media Type Method of Distribution <br /> Pressure Bed(<6%slope) Rock Pressure <br /> Gravity Bed(<6%slope) Chamber Drop Boxes <br /> Trenches Graveliess Dist.Box(<3%slope) <br /> Other: Other: <br /> 6. TRENCH OR BED BOTTOM AREA <br /> J. For trenches with 6 inches of wide wall beneath the pipe or 10"diameter gravelless pipe: <br /> A x H= 450 gpd x 1.67 ft/gpd = NA ftz <br /> K. For trenches with 12 inches of sidewall: <br /> A x H x 0.8= 450 gpd x 1.67 ft/gpd x 0.8 = na ftZ <br /> L. For trenches with 18 inches of sidewali: <br /> A x H x 0.66= 450 gpd x 1.67 ft/gpd x 0.66= na ft2 <br /> M. For trenches with 24 inches of sidewall: <br /> A x H x 0.6= 450 gpd x 1.67 ft/gpd x 0.6 = na ft2 <br /> N. For gravity beds with 6 or 12 inches of rock below the pipe; <br /> 1.5 x A x H= 1.5 x 450 gpd x 1.67 ft/gpd = NA ftZ <br /> 0. For pressure beds with 6 or 12 inches of rock below the pipe; <br /> A x H= 450 gpd x 1.67 ft/gpd = 752.0 ft2 <br /> 7. Trench and Bed Dimensions <br /> P. Select required square feet of bottom area re uired based on depth of rock/gravelless pipe or height of chamber slats <br /> 752.0 ft` <br /> (must use 6'o(rock square footage fa beds) <br /> Q Select width of trench or bed 16.0 ft <br /> (use 3'for gravelless pipe.width of chamber or width of excavation fa rock in trenches 8 beds can not be wider the 25') <br /> R. For trenches or pressure beds the lineal feet required=required square footage I width of bottom of trench or bed <br /> 752.0 ft` / 16.0 ft = 47.0 lineal feet <br /> S. For gravity beds the lineal feet required= 1.5 x required square footage I width of bed <br /> 1.5 x 752.0 ft` / 16.0 ft = NA lineal feet <br /> 8. Rock Sizing and Volume <br /> T. Depth of inedia below pipe 0.5 ft <br /> Cubic feet of rock needed=Rock depth below distribution pipe plus 0.5 foot times bottom area: <br /> (Rock depth+0.5 foot)x Area(J,K,L, M) <br /> ( 0.5 ft + 0.5 ft) x 752.0 ft2= 752.0 ft3 <br /> Volume in cubic yards=volume in cubic feet divided by 27 <br /> 752.0 / 27= 27.9 yd' <br /> Weight of rock in tons=cubic yards times 1.4 <br /> 27.9 x 1.4= 39.0 tons <br /> Add in 10%extra for constructability= 1.1 X 39.0 = 42.9 tons <br /> 9. Layout <br /> Select an appropriate scale;one inch= 20 ft <br /> Show pertinent property boundanes,rights-of-way,easements. <br /> Show location of house,garage,driveway,and all other improvements,existing or proposed. <br /> Show location and layout of sewage treatment system,weil and dimensions of all elevations <br /> I hereby certify that I have co ted this work in accordance with all applicable ordinances,rules and laws. <br /> (signature) _�Z� (license#) /a�-�0 (date) <br /> NOTE <br /> Page 2 of 2 <br />
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