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PR�SSURE fi�ISTIZT�LTI'IOI�J�SY,TEM �
<br /> �
<br /> GeotexHle fabric
<br /> l. Select nu � �:.:.., �:.,;��:�..s�� � ., o .a; . �
<br /> mber of � C`��7 Y a°'�.�:p��F. .�b;, n
<br /> erforated laterals .,'i:... ' c;'?k.U•��o:,..;U.lf,1,�tl" c.•ara-�'r,'�e^:.�•,ea:.�c��.��:...;.;s:f,:�.:�
<br /> P _ � . . .. M�.n.o:•a,:�•:s...o;.,.r:�„���'�. ,r�o��,:
<br /> �varter 3nch erfozaHons s ace ""''�`�J�� '��'
<br /> , , d�3' �='�;✓�
<br /> 2. Select _ .`�,�:��':<; �� � f�;ri';i�:4;;.;�4 ;a;.';,:;�. � `�..:,a..�:
<br /> _ perforation s � � D, �• .. r:+i�.���r �: ;a:� ���a;���,.�.
<br /> P c`L C I I I g' .— .�1___--fe�le �:1 F. .d.V� r t:��:..s::c sc 1�:�:1 P.�ra,,� �,; a..;r;,; <:'.4.�':Yy,:. o'o:?`lr,.�r��i
<br /> �,:�i.�'1ii.,g:��:�_�'rh`.,qcx�:��}a',cJ�- [`i::��.131c_�r^� �:o. o��:.,�,i•,r��.�,
<br /> • - �t.� ��.7 G:e,:q oo�c.�c � ;`r �.�e,�47;r,r,�r.nl):,li[��l,-;����.j:{.��
<br /> � �Ci� � [.l:y�'�_` .17:;�j ri, w'1'� .;I�L o� ,..�a . �i.�'�,,,:G;; ..
<br /> .a:;:�.�,,., a•.�.r; t r7;.,rb� :a ��.s��tr',•n;�;�;:z��;;�-c•r.o�'i�ti;o
<br /> 3. Since perforations should not be placed closer than 1 ft. to� Perf Sp�g i 5�_5?/4��
<br /> the edge of the rock layer (s'ee diagram), subtract 2 ft, from
<br /> the rock layer length, a,�► ;3.�, -. � ��,:,��.��.,, S,,;.��� _ i,� .
<br /> ��^T��' � =�c� �':�i>� � � �� ��;�,�a� �� Perforat(on Dlscharges In gpm
<br /> , ��;3fi ��!o '3z;`sk�'-tZ
<br /> o� ayer �,g -2'ff. = fee�, "�`'��"�'� �`� p�rforatlon dlameter
<br /> . . ����=F��;��r��tka�..st.� head� � Inches .
<br /> 4. Detezmine the number of spaces betwee�z perforations. (feet) 7/8" 3/16 7/32 1/4
<br /> Divide the length above b �rforation spacing and rouncl ���� �'�$ C1•42 0.56 0.74
<br /> down to nearest whole n mber.
<br /> . _ 2•�b 0.26 0.59 0.80 1.04
<br /> Length perf. spacing— ft. � . 5.0 � 0.41 0.94 1.26 1.65
<br /> ft. =_
<br /> ( r�l spaces o:UsA 1.0footforsinpie-famllyhomes.
<br /> . � `3) ' � / b Use 2,0 feet for anything else.
<br /> 5. Nunlber of perforations is equal to one plus.the number o� ' Potentlolforplugeing ,
<br /> perforation spaces . .
<br /> _ .�
<br /> spaces + 1 = per$mrations/la�exal Ma'cilnum number of quarter inch perforaHons pei
<br /> . lateral to guamantee<10%discharge variaHon
<br /> 6. Multiply perforations per lateral by ntun.ber of laferals to � Ps f a�gn i
<br /> get total nuznber ot.perforations. �feet) 1 4 � �3� �
<br /> � . 2.5 14 1S 28
<br /> atera X ers — '� p perforations: . � 3.0� 13 17 26
<br /> p aker
<br /> Calculate the square footage per perforation (6-10 sqft/ erj) i�.3 1� 16 25
<br /> System area: ' x _ . . F' o �.1 15 23
<br /> `� 5.0 10 14 22
<br /> ��� — er ora ons V �`�----_�`� _S�fdperf � . .
<br /> 1• Dete � M4N�FDlD�LOCq7ED AT ENp OI' PflE551niE Oi5T71IBUT1oN SYSTEM
<br /> rmine required flow rate by multiplying, .
<br /> number of perforations by.fl'ow per perforation � �
<br /> � �� � �,.r^
<br /> 1'�� ^�.��Y+, . 'e
<br /> �t� X �c.� � ' .,�,�
<br /> �� gpm per -���� • "��
<br /> � � / '�„����.
<br /> H. If laterals are connected to header pipe as shown on upper s`� ��^'"""��� ���'gJ�.�rt
<br /> example, to select ininimum r;equired lateral diameter; enter ���
<br /> table with peTforation spacing and ziuznbe:r of perforations �
<br /> per lateral. Select nunimurn ,c�iameter for � u�°��F�Ep��TEo��pE LQENaLS,��
<br /> n[0luqE oiar�ne�rion v���ouwo
<br /> perforated lateral = I����� • inches. ��M�����n
<br /> p� a�, , �
<br /> .�M„o.��o�.- ���.�
<br /> F.Y1Lw a�AN`r`N�:f�.l�e,. A�.�rva�i .
<br /> . 9- If perforated lateral system is attached to nlanifold pipe ne�r. R,w,; „�a
<br /> r�;���
<br /> the center,lower diagram,perforated lateral length anci b � �"'�`.`� �.,.
<br /> number of perforations per Iateral will be approximately.one .
<br /> half of that in step $. Using these values,select minjnium � � "'�'�'��is��ti��,
<br /> .,��.. �.
<br /> K�,rv^°�P`"��n'�
<br /> diameter for perforated lateral�� �------- � � ,, �.�;b��:�,�,
<br /> __:iiiches. � � �,,,�
<br /> , ' �
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