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' ��J1�II� ���,��'I'I�I� PROC����7�� <br /> �110 ��$�1"Ilfl1YY1� �lA%Y�� ���3�Cfl��7: �� �� �Y� <br /> .. 1�. G�'�aJlt�l �1S$�'Il�1��IlOd� <br /> �. Minunum required discharge is 10 gpm <br /> ?.. Maximum suggested discharge is 45 gpm. For other <br /> estaUlishments at least 10%greatei-than the water supply rate, <br /> Uut no faster than the rate at which effluent will ilow ottt of th� <br /> dish-ibution device. <br /> lE�o ��°�e�����e ��s{t����atfl�� <br /> See pressure c�istributiort work sheet <br /> ���� I-� ��- � S�l���e� ��n�a� ����ci�y: �.� ���� <br /> �7'z- <br /> �. �����-��g�� ��n��p ��a��ir���y�n��e���ut�: rvti�1�-�1-���� <br /> A�. Elevaiion difference between pLunp and point of discharg�? st�il°#reatment system <br /> / feet �pointeof discharge <br /> -T- <br /> QhOp.Dp°`Qu':. <br /> IEB. Special head requirement^ (See Figa�re�t right- Special Head Requirements) total pipe <br /> "`""" feet length <br /> inlet ��_`�""�'r""`-' 2A.elevation <br /> �. Calculate Friction loss �= difference <br /> pipe ;� <br /> �� ------- -- -, <br /> 1. Select pipe diameter ` °� ° <br /> �. � �' .., -- ��' �� <br /> :, <br /> �---------------------------- - -- - <br /> '?. Enter Figzcre E-9 with gpm (lA or B) and pipe diameter(C1). <br /> Read friction loss uz fe�t per 100 feet from Fig�u-e �-9 Specia� Head Requirements <br /> Frictioil Loss =� , � � ft/i,l00ft of pipe Gravity Distribution 0 ft <br /> 3. Detenrtine total pipe lengdl'.hom pump discharge to soil treatanent Pressure Distribution 5 ft <br /> discllarge po�inL Esfiimate by adding 25 percent ta pipe lerigl:h�or <br /> fitting 1oss. Total pipe length tiines 125 - equivalent pipe le:r�gth _ <br /> /v feet x 1.25 -_�_feet E-9: Fractinn Lo�s in PlnsPic Pip� <br /> 4. Calculate total friction loss by multiplying frictiori loss (C2) Par 1n0 finet <br /> in¢t/100 ft by the equivalenfi pip� length (C3) and divide b 100. nominal <br /> y - �ipe diarr�eter <br /> = f,� ft/100ft x E � =100 - � ft ��OW P4P� 1.5" a" 3�� <br /> - Fl Rl <br /> ?L. Total head required is the sum o:f elevation differ�nce (A), special �0 2.47 0.73 0.11 <br /> head requiremenEs (B), and total friciion loss (C�) 25 3.73 1.11 0.16 <br /> `_�_ft+_ --- ft+__�_It = 30 5.23 1.55 0.23 <br /> �'�+��� �c��l�: _-�(.7 ���� 35, 6.96 2.Ob 0.30 <br /> ---- �"°'�°a��-�.-...�... -- .�� 4� 8.91 2.64 0.39 <br /> � :�� .�'R.�IR�fl]�➢ ������g�g� 45 11,07 3.28 O.d8 <br /> 50 13.46 3.99 0.58 <br /> A puinp znust be sel�cted to deliver at least 2,J __�rr� 55 4.7b 0.70 <br /> (lA or}3) with at least �'� f�et of total head (2D) �'� 5.60 0.82 <br /> y�� 65 6.48 0.95 <br /> -- ,�`�°�` 7� 7.44 1.09 <br /> I h�eby certifj��a�have ompleted this work in accordance with applicable ordinances, rules and laws. <br /> � <br /> � _ � � � ..,,�.,�.�.m-.�.�...,, si a � ' . <br /> ( gn ture) �`�' _(license�l#) � -aZ V"'C`7 <br /> - � (date) <br />