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2008-00113 - septic
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2008-00113 - septic
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Entry Properties
Last modified
8/22/2023 4:29:56 PM
Creation date
6/15/2016 11:10:03 AM
Metadata
Fields
Template:
x Address Old
House Number
475
Street Name
Deborah
Street Type
Drive
Address
475 Deborah Drive
Document Type
Septic
PIN
3111823230004
Supplemental fields
ProcessedPID
Updated
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I�OLJ1iTD DESIGIV V�ORIC S�-I��T (For Flows up to 1200 gpd) <br /> 1�. Average Design FL,OW — <br /> A-l: Estimated Sev✓age Flows i�n Gallons per Day <br /> num er of <br /> Eshmated �1 SO _ gpd (see ffgure A-1) b�drooms Class I Cl�ss IB Class IBI Cla$s BV <br /> or measured x 1.5 (safety factor) = gpd 2 soo 225 �8o bo% <br /> 3 450 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPT'IC B'ANI< Capacity 5 750 �150 294 in the <br /> �K�s-Srr-�.� �fl�-�`�s 6 900 525 332 Class I, <br /> /oo� � i.�on sY�,-�gallOns (see figure C-1) � 1050 600 370 II, or III <br /> 8 1200 675 408 columns. <br /> �. SOILS (refer to site evaluation) C-]: Se ticl'ank Ca acities(u� allons <br /> � Number of Minimum Liquid Liquid capacity with W���d�sposal�& <br /> 1. Depth to restric�ing layer = �Z, 1 �6 �.� feet Bedrooms Capacity garbage disposal lift inside <br /> 2. Depth of pei•colation tests = /.� feet z o�ieSs �so �izs <br /> 3. Texture ����( l.oAv�/{ 3or4 �ooa 15� �5ao <br /> 5 or6 1500 2250 Z000 <br /> Percolation rate )��.�o rpPl 7,8 or 9 2000 3000 3000 <br /> 4. Soil loading rate ,�-��_gpd/sqft (see figure D-33) <br /> 5. I'ercent land slope �> % <br /> 1D. ROCK L,AY�IZ �I1�IENSION� <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> �1 S�� gpd x 0.83 sqft/gpd = (��,��� sqft-t�i���� ���t°� <br /> 2. Determine rocic layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd >: -- � �_ gpd/sqft = ,�� ft �O�.�P^l� �L� <br /> 3. Length of rock layer = area =width = <br /> �sqft (D1) - �_ ft (D2) _ �� ft � 1 �0 �/1 PI < 1 � <br /> �. �ocx voLUM� > 120 I�PI < � <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> �o�� sqft x 1 ft = Lo�cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get ciubic yards <br /> (o��!� cuft -= 27 cuyd/cuft = �,� cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rocl< in tons <br /> 2�-:� cuyd x 1.4 ton/cuyd = 3 5 tons <br /> ID-33: Absorption Widt9�Siaeng T�ble <br /> F. S�WAGIE ABSOI[�PTIOlm1 �IID'I'I-� Percolntion Rate L.oading Ratc <br /> in Minutcs per Soil Texlure Gallons Absorption <br /> Inch per day per Rniio <br /> Mp�1 s uarc foot <br /> Faster than 5 Coarse Sand 1.20 ].00 <br /> Medium Sand <br /> Absorption widtll equals absorption ratio (See Figure D-33) LoamySund <br /> Finc Sand <br /> times rocl<layer width (D2) �b�o 3o I,oam o.bo �.00 <br /> 3]io 45 Silt Loem 0.50 2.40 <br /> ���/� X �(a _ lt = c�,�'i�� ft 46to60 SandyQayLo 0.45 2.67 <br /> Silty Clay Loam <br /> t3Y_lA• <br /> 61 to 120 Silty Clay 0.24 5.00 <br /> Sandy Clay <br /> Cla <br /> Slower than 120° <br /> •Sys�cm daigncd!or tliese wils rm�st bc oWer or performnncc <br />
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