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' �IZIESSURE ]DISTRT�U'I'�ON sY sTE1VI
<br /> GeoEextile fabric
<br /> l. Selectrtumberof erforate `� :�: ., °.°""�.s'� �'�`p��� ' D `, _. � " '
<br /> p olaterals .:a��```:71;?�S�So;n,a�'p;, °fl�b''r.°a.�: 'r.;�o?�. i.a�.�a�.' e�,.
<br /> ..�� . 3 �{�:.. R`5.n.o'..:��c�.:.,.� n'i•.:;�;.���;:.,:.;c.:'iq'`
<br /> - —�---__ • rr�.:.r�od:. � � ��6�"'<}
<br /> uarter 3nch erforations s '�-�r_<�,
<br /> aced�3' +,-a. '�" `�
<br /> �. �� .L�d�{?ifT?��-�..Z.��.��;:�' � :..�;.;.-P`Q�w oc;_�•`d?'����,t�H: ' �;.
<br /> Selectperforati p , g ;'. .. �r.,.1¢. c r�.:z1i 4 :,�o t �;'Sr: �:..,_-��,;�.�:.:;�: ,.,
<br /> �IZ.S C�C�g— .,�1-� ��e�L. �:JE'C?''Q:�:,�F:��'S:.:qO�c'�9!'a°�il.S4 c": �,.o..}i(�. 0�� �.,}i;n;i•'(...ao:�:l�i\�1:
<br /> ----___ �,:�7..hi.,rt:�,:.�_..5,:��xt��`�7ot.b;.�c7- ;`i:=QJ,�,13� � r.c.�rr�:,�.�:•,;;��n
<br /> . :..,[.I/ti�.7.L,��:;C).Q.:"ti:.e>>�Jio�� s�' ��e 4'.�.�,.,er,�o-nQ.'u25��,�,"����:
<br /> . ,o�:rr.c�:�., o�.�.I.:C7"C? �(ii �v�co;``�i���"...a ' ..n?>'..��f.',� ���• ���
<br /> . � L 17r•=.�;Q� _ r>.5-3l/;:�.n:�r1S�.�r�;r, riii;j[o
<br /> 3. Since perforations should not be placed clo�er tllan 1 ft. to� Perf Spacing 1.5�-s� `I` ' I`
<br /> Perf Sizing 7/32"-1/4"
<br /> the edge of the rock layer (see diagram),subtract 2.ft. from
<br /> ilze rocl<layer length. �
<br /> P�rfo�affon dlscharges In gpm
<br /> � �`� -2 ft. = f,�C�� �eef, m pertoratlon dlameter
<br /> oc ayer eng _
<br /> � � head Inches
<br /> 4. Determu�e the number of spaces betwee�l perforations. (teet) �/8" 3/16 7/3� ��q
<br /> Divide the length above by perforation spacuzg and rouncl ���� �'�8 ����2 0.56 0.74
<br /> down to nearest whole mimber. 2.ob 026 0.59 0.80 1.04
<br /> Lengtlz perf. s acin � ;, . 5.0 0.41 0.94 1.26 1.65
<br /> P g= ��:_. ft. :- = = ft. _= .�:� .
<br /> ( ( ��`iCeS °UsA 1.0 foot torsln�le-famlly homes.
<br /> `3� l�� b Use 2.0 feat far anything else.
<br /> 5. Nunzber of perforations is equal to one phis.the number o�f ' Potentlalforplugging
<br /> perforation spac�s _ �`
<br /> _ �
<br /> �'�t�. S aces -+- 1 = `�(�� Maxintum number of uarter inch perforaHons pei
<br /> P �er�ox•�tior�slla�ex•a1 q
<br /> lateral to guarnantee<10%discharge variaHon
<br /> 6. Multiply perforations per lateral by num.ber of laterals to � �s fer�gn / �
<br /> get total number of.perforations. � � 1 4 1 2 �
<br /> . . �-5 �� 18 28
<br /> ,, ;., �, ,
<br /> atera x pers atera — '�'"'''�I��Ifo�ations: �eo' 1� �'7 ��
<br /> Calculate the square footage per perforation (6-10 s ft/ er1� ��3 �� 16 �5
<br /> System area: �c�' �c���;' _ �,.:,��> . `� P � �.� 11 15 23
<br /> t,�r>� _ �� �. �f./
<br /> �.� �-� 14 22
<br /> area � er ora ons V � ` �" s�fdperf � .
<br /> 7- Deterrnine required flow rate b�r multi 1 u1 , `"'N1F°�o �orJ,�o �T �Idp p�: ppESy��jE OISn71t7UT10N SYSTEM
<br /> number of perforations by.flow per pePr or��on �
<br /> � wr�.r^
<br /> �
<br /> ' ���
<br /> (,�`� r �l�-1 _ r• � �
<br /> �� X SPm peT � ��m ' �j.
<br /> / t„", (�
<br /> 8. I�laterals are connected to header pipe as show7Z on upper �"r`� Ss`�ci�P9.`�J��
<br /> ��rt�
<br /> d��
<br /> e�cample, to selecf ininimum required latei�al diarneter; enter �
<br /> table wit�i pei�foration spacing and riumbe:r of perforations
<br /> per IateraL Select iriinin-itun c��iameter for �~'�'�°F����DMiE���pE LaTENn�S,��
<br /> PnE9lufiE 019T1��9uf1oN Y���ou��o
<br /> perforated lateral = � ira�gi�s. �>"�°^�'°�•�•°„�•�
<br /> ,
<br /> { „o..,s-.Qo�� .�„�
<br /> EylEw D�SArir s[�:��i fio. A MKay .
<br /> 9_ Tf perforated lateral system is attaclzed to n.lanifold pipe near. ,,w.; a o,.o„��a
<br /> r;.,,�,o
<br /> the center, Iower diagrarr�,perforated later�al lei�gth and ����F`
<br /> 'a �
<br /> number of perforations per lateral will be�pproXljnate.ly one . �-'�'t�'�"��°�^-'�'�
<br /> half of that in step g, Using these values,s��lect minisriurn �����f b`
<br /> �R�LO`�E�IL
<br /> diazneter for perforated lateral.� I�1 a.�v�," fli�cli�es. � � ��^�°''"� ""``,�"'�°`�
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