Laserfiche WebLink
, , MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. �.QW Fatimaced Sewage Elows in cnl►oos per day <br /> ( d) <br /> Estimated �'�J gpd ra� �Tra� r�n r�m r� <br /> or measured x 1.5 = gpd. <br /> z 30o zu iso �, <br /> B. SEPTTC TANK LIQUID VOLUMES a 6 0 �°s 2� oft°` <br /> 5 750 450 294 � <br /> ��;C� d�0I1S 6 900 525 332 m <br /> � 7 ! 1050 600 370 Tra� <br /> Qa <br /> ; 8 i I200 675 408 I m <br /> C. SOILS (refer to site evaluation) ' `°'"� <br /> . . T..� �. � <br /> 1. Depth to restricting layer= �� inches i � feet ��, <br /> r��r ��� . . �� M�m� <br /> 2. Depth of percolation tests = /a inches � � •r+�� uh� <br /> 3. Texture ` ���- Percolation rate �/ mpi 23 K:" �� �� � <br /> 4. Land slope `/ % �SR�Ky 2� � °� <br /> D. ROCK LAYER DIlvIENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> ��� gpd x 0.83 sq. ft./gpd = �3� sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ '� ft. <br /> 3. Length of rock layer = area =W��4l � �'�r t'� � �� • a <br /> «�:O' �� O� N. <br /> ,��}�' �y* Q <br /> n�,� sq. ft. _ �Z ft. _ >��ft. -'�..o.��.;�, Q� <br /> rro'�"r,.� .�.�..a. <br /> d. ,,. 4..v o c D p; <br /> W1dtll�ft .� � � a.a � D •. <br /> <120mpi <10' Length � ? ft <br /> E. ROCK VOLUME <br /> >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �'� sq. ft. x /,��' <br /> ft. - �6�= cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��� cu. ft. -:-27 = a��.; cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; 2y s cu. yd. x 1.4 <br /> ton/cu. yd. =3�� tons. <br /> F. ABSORPTTON WIDTH �;�w�n s�� <br /> 1. Percolation rate in top 12 inches of soil is�mpi ��m ��Ta� �y� wo�A� <br /> Texture �f'%�' cMa� <br /> �co« tay«w,am <br /> Faua t6an 0.I Coatse Saod I.20 I.00 <br /> 0.1 w 5 Saod 1.20 I.00 <br /> 2. Select allowable soil loading rate from table; o.��s F�s�a o.�o z.00 <br /> _.1¢..L d/ft2 aw�s s�a,�� 0.�9 i.sz <br /> , is w 30 ►.� o.bo i.00 <br /> � 31 w45 Silt Laam 0.50 2.40 <br /> 46 ro 60 Clay L.oam 0.45 2.67 <br /> 60 to I7A Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�o..«��zo c�Y o.�0 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ ,�� �d/�_ � <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> :� x /0 ft=,�;2_ft <br />