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1999-012056 (new septic)
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2120 Carriage Lane - 10-117-23-24-0036
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1999-012056 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:14 PM
Creation date
2/17/2016 11:09:27 AM
Metadata
Fields
Template:
x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
Supplemental fields
ProcessedPID
Updated
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�; I�()�'V N�I.C)PF I3ERM W I I )�I-1 1 •.���,,,� < <"��� � <br /> 1. If landslopc is 1% or more, - � <br /> subtrac-t mck layer width frc�rl� .3c3s��r��tiun width � a�.� �o� ,� � <br /> � K�k t ,o d" <br /> tp 0�1tc31Il iT11711211L1IIl C�OWT1S�O�E bC'i"Tll tOl' (lean Sand <br /> 2r..� � - �� � = 1�� _ fPPt - - 6..ToPso� <br /> a�ural So�l <br /> _'--------- <br /> 2. C�alculate Minimum mound 5izE� <br /> a_ Determine depth of clean sand fill at ��r���,,N w„i,n �<,�i��w�d,n <br /> upslope edge of rock layer. ---- -- — R�W�a� q��hon Width <br /> Separafion 3' - 2 ft = __�_ feet -- -- <br /> b. Add depth of clean sand for separation (2a) <br /> at upslope edge, depth of rock layer (1 foot) to depth of cover <br /> (1 foot) to find the mound height at the upslope edge of rock layer; <br /> l ft + lft + lft �_ feet <br /> c. Enter table with landslope and upslope berm up ope Width <br /> ratio. Select berm multiplier of � • 23 . b <br /> d_ Multiply berm multiplier by upslope mound� uPs�`"�a�� a°°'^p°°°`^R°�k Bed '°^�°'°4 8 UP��fl�W�dth <br /> I � '` e< 1N�idth (� eeoe o� <br /> height to find upslope berm width: Ha oda,p000• 1—�ovoa;�oaD a <br /> < < L,en aa a <br /> Qo o�o� Qo Paa 0a�� Qa�Qa o o. <br /> S a... �u oe�-Y <br /> `�.�Z x 3-2�—�� feet � <br /> e. Multiply rock layer width by 3 : <br /> A <br /> landslope to determine drop in elevation; �° ` n��io�wathT�9 - <br /> a Absorption Width /6 7 <br /> _�x�/o= 100 =Q�6 feet <br /> f_ Add depth of clean sand for slope <br /> difference (2e)at downslope edge, to r°`��"� <br /> the mound height at the upslope edge <br /> of rock layer (2b) to find the downslope height; <br /> �.C� ft + •�6 ft = 3.�feet <br /> g. Enter table with landslope and downslope berm ratio. Select <br /> berm multiplier of S-26 <br /> h. Multiply berm multiplier by downslope mound height to get <br /> downslope berm width: <br /> 5.26 X 3.6 =� feet <br /> BERM SLOPE MUL'I'IPLIERS <br /> i. Compare the values of step G.l l - 7 <br /> and Step G.2h /P. � �a DOVVNSLOPE UPSLOPE <br /> S� berm muldplias for various Eerm maltiptias tor�ariau <br /> Select the greater of the two values as the �� n�,���,d� ���,d� <br /> downslope berm width; feet <br /> j. Total mound width is the sum of � ' ° s� ' '� � ° � 5 � � � $ � <br /> upslope berm (G.2d) � ;-a a.o s.o 6.0 �.o s.o a o s.o b o �o s.o <br /> width plus rock layer width (D.2) ' '09 ° i� s.�b 638 �s3 z.v� 3.ss a�b s.� e s� �a� <br /> '_ 3 19 a 35 5 56 6 82 8.14 Z83 3.70 a W 536 6Ja 6.9p <br /> plus downslope berm width(G.2i); 3 ��0 4 s4 s gx �3z s s� �.�s 3s� a 35 s os s�9 b as <br /> � � + 1� ft + l�' `jft - � feet a is! .�?6 625 789 97? ?6fi 3a� 4I7 aKa Ss6 606 <br /> k. Total mound length is the sum of upslope s ��: s cx� 667 a.s� io.�� z bi 3 s� a oo a�� s iv s�i <br /> berm evidth (G_2d) plus rock layer length (D.3) � 3 c�, s ,c> ; „ 9 3s iz o� �u 3 z3 3 as :,a, ,9� s 4, <br /> plus upslope berm width (G.2d); � ;su s �� 7 69 io�a i3�; z aa � i: 3�o a z3 a�0 5 13 <br /> � ft + �ft + � ft = feet H �9� 58� 833 II.S4 1591 232 303 357 �i05 �49 4g8 <br /> 9 9 9 II 625 909 I304 I892 236 294 ;AS 390 -730 46S <br /> � 10 �29 6 67 Iu 00 I5.00 23.3J 2.31 '-Sb 3 33 3 75 a l? a 44 <br /> i Final Dimensions: �i aax � ia ii ii n�s 3oa1 zz� ��F �z� ��i ivs a :�, <br /> 12 7 t�v 7 6v 1250 21-43 4iJ5 2:1 '70 3 12 3A9 3-80 4 OS <br /> �6 x D <br />
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