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1999-012056 (new septic)
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2120 Carriage Lane - 10-117-23-24-0036
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1999-012056 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:14 PM
Creation date
2/17/2016 11:09:27 AM
Metadata
Fields
Template:
x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
Supplemental fields
ProcessedPID
Updated
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L.p� ✓ <br /> , � . MOUNI� [)I�:til<;N l�'OIlhtit�l�1�:�1 <br /> ({��,r I�l�n��� iiE, t�� 1?(1O �;�,�il �/�2-�� -5��� <br /> �. I�1.��1� --- i Isuma�ed Sew�gt f-lows�n Gallom���a�. <br /> i <br /> �Sillllij�('(j _��_ �d INumha ITyptl T�ef1 T [II ��T-� <br /> c�r mc�asured _ x 1.5 =_____ K}��� "' ra � <br /> � �oo us iso -__---- <br /> � a 50 300 2 I A �`�' <br /> Fi. SF.PTIC TANK LIQUID VOLUMES , � „s z� of,� <br /> a�i�o ��� <br /> __ gallons I � � s� �� ; �, <br /> , � �oso � 600 3�0 � ' "� <br /> X i 1200 + 675 I 4Q8 � IIII <br /> C S��ILS (refer to site evaluatic�i�) � �� �� <br /> ' Taak w�w(r �Wwi � <br /> 1. Depth to restricting layer = fa`�_ inches Z•D fe�t ��Wa��,�,,. <br /> u�me.�,,�i wdmwo t�w�a �.Wd c�aan..,w .,,u,msr��wa <br /> 2. Depth of percolation tests = /Z inches ���•�� �a�r s��m=� �,h„�„� <br /> 3. `Texture CIRy loar� Percolatic�n rate 17-20 ��•'�` '�° "u ,� <br /> m pi ,.,• i000 isoo �000 <br /> s.��� i soo _zso �000 <br /> 4. Land slope % ��,•,� _�, ,� .,,,�, <br /> D_ ROCK LAYER DIMENSIONS <br /> l. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �_gpd x 0.83 sq- ft-/gpd = 6�0 sq. ft. <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') _ / v ft_ <br /> 3. Le�rock layer = area �width = o0 00 0 �e e ,00, o, e �� <br /> sq. ft. � ft. � ft �S�a°>nD�D�oo�o� � . <br /> da�4���d�:be.o0:�0nD vD D <br /> x <br /> Width 10 ft aoo � 0000n D ea ` <br /> <120mpi <10' Length_��ft <br /> E. ROCK VOLLJME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 630 sq. ft x 1 <br /> �- _�_cu. ft. � <br /> 2_ Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 6�cu. ft. = 27 = �3 cu- Yd- <br /> 3. Multiply cubic yards by 1.4 to get wei ht of rock in tons; cu_ yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F_ ABSORPTION WIDTH Absorption�dth Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is y6-C�� mpi �d,��w,�,o c��� a,aoor��, <br /> T�'X�lr�' � C��� M�nwcs per IocA $oil Tczturc per day per wid�b�o Rock <br /> (MPI) squarc fovt Lava W'�d�h <br /> fuicr Nu�0! Coarzc Sand l._'0 1 00 <br /> 2. �lect allowable soil loadin�; ratc� frc>m table; u���, f�a'°s�,a o�bo �«, <br /> '^ 6�a 11 Sandy L.win U 79 I$2 I <br /> ♦J � `iS'�-gpd/ft= �<,,,�;� � o� �� <br /> 1 I to dS $ilt Loam 0 SO '_10 � <br /> a6�o t�(i Clay Loam 0_45 2 67 <br /> 6G�o 1_0 Cl�y 02S 'Tap' <br /> 3- Calculate adsorption widt}t rati<� b�� dividing rock laver s'°�"°�'"o c��� o�o ew <br /> Ic�ading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft== gpd/ft� _ . 2>67 <br /> � ;�lulti�,l�' a��tic�rptint� �,�ic�th rah�� 1��� ►u��►, la����r �ti�idth t�� �;��t <br /> rryuired ads�rption wic�th; <br /> 2•62_ x �v — ft = �� ft <br />
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