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<br /> EIO PfftRMAT10N Or ♦ PfR�(Nt41En L4iFRAl
<br /> A. Determine pump capacity: _w��
<br /> Gravity Distribution '-- -�
<br /> 1 Minimum su�,.cslcd is 6(Xl gallons pc�n c�iur(10 gpm) Ic� stay ahcad o( ��� 1
<br /> watcr usc rate. . �...,s«�... �;,�,",.=:"`":,`,.'�:"�-^�,
<br /> � �,,..,,
<br /> ��,�,�..�
<br /> 2 Maximum su�esMd for delivcry to a drop box o(a home system is 2,700 'T '-�^�^��^^a����,.<,,,,,
<br /> . . ....� �.., w, �
<br /> �allons per hour(45 gpm)to prevent build-up o( pressure�n drop box. r,,-p� ; -u ,.,,, ,:•„�ao.
<br /> w�e ei ne���,,,
<br /> �.n..a�w�.�w�.a.i
<br /> Pressure Distibudon �,�„�„� a.,..,,,«�.,..,,
<br /> 3.a. Select number o[perforated laterals
<br /> b. Select perforation spacing= feet �o^rW sou ►�w.+r scauw
<br /> B�lan Pbop$rd Larw
<br /> c. Subtract 2 ft from the rock layer length.
<br /> „���-2 ft_= feeti
<br /> d. Deternune the number of spaces between perforations.
<br /> L.�Il$�}1 �f-Sp3cing= ft. + ft.= spaces Requued Petoraeon Discha�e
<br /> e. spaces+ 1 = perforations/lateral m g�uons per a,u,�ce f
<br /> f. Multiply perforations per lateral by number of laterals to �ls�t,�ge
<br /> get total number of perforations. W�� x – erforations. H�d �2��' � "d R,,
<br /> ��a�,- P (f�)
<br /> g" � x�_�+= gPm.
<br /> I.Oa 0.56 0.74
<br /> SELECTE'D PUMP CAPACII'Y LI� gp� 2.0� O.HO I.O4
<br /> B.Determine head requirements:
<br /> 1. Elevation difference between pump and point of discha a_ Use for single family homes
<br /> Z �• b.Use for all other applications
<br /> �_feet
<br /> 2. If pumping to a pressure distribution system,five feet for pressure
<br /> required at manifold if gravity s tem,zero.
<br /> � feet
<br /> 3. Friction loss
<br /> a. Enter friction loss table with gpm and pipe diameter. � Pipe Lengch
<br /> Read friction loss in feet per 100 feet from table. ' Poinc of Dischargc
<br /> F.L- �Db h,/100 ft of pipe
<br /> b. Deterrnine total pipe length from pump to discharge 0c���,D���T
<br /> pointi Add 25 percent to pipe length for fitting � 1
<br /> loss,or use a fitting loss chart. Equivalent pipe P
<br /> length-1.25 times pipe length -
<br /> _J('(�x 1.25 = , feet
<br /> F-18b
<br /> c. Calculate total friction loss b multi t n 1_S inch 2.0 inch 3.0 inch
<br /> Y P Yl g � fiiaim Im pa 100 h d P�pc
<br /> friction loss in ft/100 h b equivalent pipe length.
<br /> Tota]friction loss= � Z x �, ZB +100= ��D feet 10 0.69 0.20
<br /> 4. Totai head required is the sum of elevation difference, �Z 0.96 028
<br /> ]4 1.28 0.38
<br /> spccial head requirements,and total fnction loss. 16 1.63 0.48
<br /> �x zo3 0.�0
<br /> 20 2-G7 OJ3 0-1]
<br /> � + � + �S 3.7� 1_ll 0_16
<br /> ---�---—
<br /> tl? (2) _ _ _--(3c) -- :0 � 5-?� 1.55 � Q2:+
<br /> lS � 7.�.X1 ?(lr; 1 p.30
<br /> "I�C�T AL HLAI� -ul 1 Lo7 �c� � p.�<� �
<br /> ��_ fcct a5 la 7; �_�s � o-aH
<br /> SU l'�) � O.Sh
<br /> ( - ['ump selection 5', ° ��' t °7('._�
<br /> �,�� �5.«� � �s�
<br /> �
<br /> � I. A pump must be selectc�d to deliver at lc�<�sl
<br /> � l � f;F'm (Sfc�� A) �ti>ith at 1��.�tif /�/ fcc�t ��f (otal h��.ic� (�t��E� fi)
<br /> �i----
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