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1999-012056 (new septic)
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2120 Carriage Lane - 10-117-23-24-0036
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1999-012056 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:14 PM
Creation date
2/17/2016 11:09:27 AM
Metadata
Fields
Template:
x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
Supplemental fields
ProcessedPID
Updated
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� PIZ.EStiUItE UIS�I_R1�UT1ON 51'$TEM ������t�•xtil��tahr��� <br /> ] �elect ntimber c�f perforated latc�ral� _____� _ 14 " <br /> uarter inc h rl��rahc�ns s aced A 3' <br /> 2. Select perforation spacing = 3 feet. y`ot ro�k <br /> 3. Since perforations should not bt� placed rl��ser than 1 ft. to Pert Sizing 7/3z'� - �/��' <br /> the edge of the rock layer (see dia�;ram), subtract 2 Et. from I'er(Spacing 1.5'-5' <br /> the rock layer length. <br /> R��d� - 2 ft. =�1_ feet. <br /> Requued Per(onnon D�sclurge <br /> 4. Determine e number of spaces between perforations. �g�«����««m, <br /> Divide the length above by perforation spacing and round °H`�` ;;�•� ;..a�. <br /> down to nearest whole number. "`"' <br /> 1.Oa 0.56 0.74 <br /> Length perf. spacing = ft. - 3 ft. _ �spaces <br /> 2.Ob 0.80 1.04 <br /> �3� �2� a.Use for single family homes <br /> b.Use for all other applications <br /> 5. Number of perforations is equal to one plus the number of <br /> perforation spaces . <br /> � spaces + 1 =�_perforations/lateral ���number of quarter inch perforations pe <br /> lateral to guamantee<10%discharge variation <br /> Perforation <br /> 6. Multiply perforations per lateral by number of laterals to SPf�tjg 1; 1 z 2 <br /> get total number of perforations. 2,5 14 18 2$ <br /> � x T =��perforations. 3.0 13 17 26 <br /> ��5 �"�� � 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying l�.Q 11 15 23 <br /> nurnber of perforations by flow per perforation 5.0 1� 14 22 <br /> 6 � �( ���—�g�JIYL. MYafOlO IAC�TED 1T EW OF vAESAJRE D6TRIBlfTiO/+ SS�EM <br /> 8. If laterals are connected to header pipe as shown on upper � <br /> example, to select minimum required lateral diameter; enter �" �� � - �a� <br /> .�-- � 1 <br /> table with perforation spacing and number of perforations ,,��'"� "-�-' <br /> per lateral. Select minunum diameter for ` � �``" <br /> perforated lateral = � inches. � <br /> ,,.o.,,�..<,..a,.,�o..t� :,� <br /> ..cssua as�.rv*�o.w..w.n <br /> �. ....o...o�n,...n <br /> 9. If perforated lateral system is attached to manifold pipe near =ro �"�'z��� "��� ��^ <br /> ' ,...�.a� J�-" <br /> the center, lower diagram, perforated lateral length and ---T''-�- , �� , <br /> number of perforations per lateral will be appmximately one ^ �'- %" <br /> � ��::�•.:� <br /> half of that in step 8. Using thesf� values, select minimum ;�,., `b `�� <br /> diameter f��r erforated lateral = �► " �� ""� �`� � <br /> P �— inches. ,� ,.�'°' � <br /> ,.��- ° <br />
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