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1999-012056 (new septic)
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2120 Carriage Lane - 10-117-23-24-0036
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1999-012056 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:14 PM
Creation date
2/17/2016 11:09:27 AM
Metadata
Fields
Template:
x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
Supplemental fields
ProcessedPID
Updated
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G. ��(��-'V NSI.OPI�, l3LIZM W I f)�I�11 �,�.,,„� _ <��.-�� � <br /> 1. 1f landslc�pe is 1% or more, � � <br /> subtract rc�ck layer width from adsc�r��tic�n width " � .�- �o� � <br /> ( Rock 1 �p p` <br /> to obtain minimum downslope berm tc>�� c-,ed1�„d <br /> �� ft - ��_ h = �_ feet -- �.Tap�'' <br /> a���ai s�a--- <br /> 2. Calculate Minimum mound Size <br /> a. Determine depth of clean sand fill at ��r����W+��n Dowrulupe Width <br /> upslope edge of rock layer: — R�w�aw q��hon Width <br /> Separation 3' - Z ft = � feet <br /> b. Add depth of clean sand for separation (2a) <br /> at upslope edge, depth of rock layer (1 foot) to depth of cover <br /> (1 foot) to find the mound height at the upslope edge of rock layer; <br /> �_ ft + lft + lft = �� feet <br /> c. Enter table with landslope and upslope berm u S�Width <br /> ratio. Select berm multiplier of �•�{�— . <br /> d. Multiply berm multiplier by upslope mound I Up pe W�dth ��o�o�Oeb��wd� �o,�D9b A�:y uPslop�Width <br /> � � 9< n e. e- oo:oo. � <br /> height to find u�slope berm width: eb oa,aoQo ���esa0e�0➢D y <br /> Qa°,q°°p°98 Len 6 ao a e o 0 0. <br /> 000�oa oQ6p a'69UyU�pw.QoQo8D�9 <br /> 3 �D x 3_�� .� feet � <br /> e. Multiply rock layer width by 3 <br /> landslope to determine drop in elevation; F m�►o�w�a�n �6• Z- <br /> Absorption Width�_ <br /> �C� x..�%= 100 = Q� feet :. . <br /> f. Add depth of clean sand for slope � ' � <br /> difference (2e)at downslope edge, to <br /> ro�t,�gcn_�2 <br /> the mound height at the upslope edge <br /> of rock layer (2b) to find the downslope height; <br /> 3•� ft +��_ft = �feet <br /> g. Enter table with landslope and downslope berm ratio. Select <br /> berm multiplier of �`1-7 6 <br /> h. Multiply berm multiplier by downslope mound height to get <br /> downslope berm width: <br /> y.76 x_�_�,�feet <br /> BERM SLOPE MULTIPI.IERS <br /> i. Compare the values of step G.l� <br /> and Step G.2h��G �a DOWNSLOPE UPSLOPE <br /> SI bam multiplias ror vu;«n eam mmupfias ror vu;«n <br /> Select the greater of the two values as the �� n����d� e��na� <br /> downslope berm width; �6- �. feet <br /> j. Total mound width is the sum of � ` ' s� ' '� 41 s ' � g � <br /> upslope berm (G.2d) a 3.o a.o s.o b o zo s.o a o s.o 6 0 �.o s.o <br /> width plus rock layer width (D.2) ' 3.°9 4.i� 5.26 6.38 �s3 z.v� ;.as a�6 s.� b.s� �ai <br /> ? 3 19 4 35 SS6 6.82 8 14 2 83 3J0 4 S4 5 36 6.1a 6.90 <br /> plus downslope berm width(G.2i); � 3�o a sa s_as ��z s sb ��s 3s� a 35 s oa s�9 645 <br /> �0� ft + /6-Zft + J�__ ft = ��.6 feef a �a� a�6 bzs �s9 9�� z� �as ai� asa sae 6ob <br /> k_ Total mound length is the sum of upslope s �s� s o0 66� a s� io.�� zbi 3 33 a oo a bz s i9 s-;i <br /> berm width (G.2d) Plus rock layer length (D.3) 6 3� s z6 ; �a 9 3s ,z o� �sa 3 23 �as ,a, �9� s,; <br /> plus upslop� berm width (G2d); � 3so s s� �69 �0�4 1373 248 3 �z 3.�0 4z3 4�o s �� <br /> �_ ft + �_ ft + _(� ft = � feet � 3 95 s aa s 33 i, s4 is vi z.az 3.03 3 s� a.os a av a xs <br /> 9 a I I 6.25 9 09 13 04 18 92 2 36 294 3A5 3 90 a 30 4 65 <br /> i �0 4 39 6 67 10(� I5.00 23.33 ?.31 ?.86 3.33 3J5 a I' 4 44 <br /> � Final Dimensions: ! �� �4s � ia ii ii i��s ►oaz zz� ��t+ 3z3 3�i �vs a :�, <br /> �,h �Z a6v 76y I2S0 21a3 437s 2?1 ?JO 312 349 �80 aO8 <br /> x , <br />
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