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1999-012056 (new septic)
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2120 Carriage Lane - 10-117-23-24-0036
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1999-012056 (new septic)
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Entry Properties
Last modified
8/22/2023 3:22:14 PM
Creation date
2/17/2016 11:09:27 AM
Metadata
Fields
Template:
x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
Supplemental fields
ProcessedPID
Updated
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� 5 <br /> . . MOUN1� f�ESI(:N WOIZK�Hf�:1�"1 � �; / <br /> (Fc�r 1=1���vti u�, 1�� 17_(1O ���c�) 7`� <br /> A_ FI.(�W I [sumarcd Sewagc Flows m(}a11���M�day <br /> Estimatt�d ��� �d ir,,,,T,nd ir�i �ryr,�a rram r� - <br /> c�r measured x 1.5 =__ g�d. "' " <br /> -� �oo z2s i so --- <br /> 1 4 50 100 2 I B �`'� <br /> E3 SEPTIC TANK LIQUID VOLUMES , � „s ,� o,� <br /> �_�1 'v gallons � `s' � � � 6o0 3 0 , �� <br /> � ,,.�, <br /> a izoo b�s I aos � °�i <br /> C. SC�ILS (refer to site evaluanon) ���� <br /> . . T�e4 �ol,a/v .unmi <br /> 1. Depth to restricting layer = 02`� inches 2� feet i,�Wa��,�„� <br /> N�mfx,�d wdm�w t� ��n•�,N .,,m m:M,c,�h <br /> 2. epth o ercolation tests = �'Z inclles �.�.� ���Y s��m,,.a.� I�h�wOr <br /> 3. 7exture l�✓"1 Percolation rate l�-za '"'�` '�° "�' �� <br /> Tp�] '�,.. i000 isoo :� <br /> � o s,��h isoo _2so � <br /> 4. Land slope �_/o �w.,.� z�, ,� ,,,� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> ?so gpd x 0.83 sq. ft./gpd - ��U Sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ �ft. <br /> 3. Length of rock layer = area =width = • �e4e4-,aoo •aAo • • ep < <br /> 6.3c� sq. ft. - �� ft. _ �— ft �-5�°�`°�°�' o�oQ n. <br /> a aD�o p <br /> a d-4 D, <br /> QaF a a be;oOoonD�p n <br /> Wld� �7T vo�:�oo�o �'4'�0�00D D o eD a <br /> a� <br /> <120mpi <10' �n��3—fte <br /> E. ROCK VOLLJME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�Q sq. ft x�_ <br /> ft. _��cu. ft. � <br /> 2_ Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 63O cu. ft_ =27 =�_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; cu. yd. x 1.4 <br /> ton/cu. yd. _ ��tons. <br /> F. ABSORPTION WIDTH Absorpdoo�dth Sizing Table <br /> 1. Percolation rate in to 12 inches of soil is�- <br /> a5%���v-z.�►P �` _ mpi �+���o �c��� r�a�r��, <br /> Textur Minuics Ixh $oil Tczturt day widt6�o Rock <br /> (MPI) squarc forn Layv Widch <br /> Fis�cr than 0 I Co�rzc Suid 1'0 1 00 <br /> 2. Select allo�n,�able soil loading rate from table; o���s F,M�e ob`o �a <br /> 6�a I S Sandy l.oam 0 79 1 S2 <br /> (�_.�� ,�d/ft` i����o � oco zra <br /> �i��,a, s���i.�, o so <br /> :w�o bo ci�Y� o as z b� <br /> ���i Zo cuy o za s o0 <br /> 3. CalculatE: adsorption width ratio by dividing rc�ck layer s��..9,h�,�zo c��y ozo hc� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft�= gpd/ft� _ <br /> -� MultiE�i}' ad�c>rpti<>i� �,�i�ith rati�� b�� r��rk la��er ���idth t�� f,��t <br /> required adsorption wic�th; <br /> �� x �_ ft = �Oft <br />
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