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2012-01021 (septic)
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2012-01021 (septic)
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Last modified
8/22/2023 5:24:26 PM
Creation date
1/22/2016 3:39:54 PM
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x Address Old
House Number
4495
Street Name
Bayside
Street Type
Road
Address
4495 Bayside Rd
Document Type
Septic
PIN
0611723210004
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�� OSTP Pressure Distribution <br /> Minnesota Pollution UNIVERSITY <br /> Design Worksheet oF Mt�vNEsoTA '''�� <br /> Control A enc �,�;' <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Laterals in system/zone: � ---- - <br /> (2 feet is minimum and 3 feet is maximum spacing) `����"�`�"" ��'" <br /> _ .. _. r <br /> 2. Seled Perforation Spocing: 3.0 ft " � "`5 ' ' __ <br /> � v„ � <br /> Min <br /> 3. Setect Perforation Diameter Size 7/32 in _' v����4�:�""���...,�,��.����,,,:,�i _ , f n�;�"��k „ <br /> (.'�l�i�ck <br /> 4. Length of Lotero(s =Media Bed Length -2 Feet. -- "°^°�.,'">^>"^„"' ,°'' `'��,�"�,"^��•,,°�'^"' ", ' - <br /> 63 - 2ft = 61 ft Perforation can not be doser then 1 foot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Laterols (Line 4)by the Perforation Spocing (Line 2)and <br /> round down to the nearest whote number. <br /> Number of Perforation Spaces = 61 ft - �ft = 20 Spaces <br /> 6. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Loteral = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check tab(e below to verify the number of perforations per latera(guarantees less than o 109�dischorge variation. The value is <br /> doub(e if the a center manifold is used. <br /> Maximum Number of Pe*torations Per l.atera!to Guarantee�1(1�D:scharge Variat;� <br /> ';In�:n Fertc�ratcn; 1i321nch Ferfor�tions <br /> r''ip?Diame.er 11ncM�s1 Pesfaratio�Spacing Pipz D�ame#�r(lnct�s) <br /> F'?�forataon Spac�ng(Fe�t1 <br /> t 1i: t: 2 3 ifeetl f tl: 112 2 3 <br /> � 10 13 1$ 3Q 60 2 11 i� 2i 34 bG <br /> 7�: Q 12 16 23 54 2,: 1"U 1�1 2� 32 6� <br /> 3 8 12 16 25 51 3 9 14 19 3Q 64 <br /> 3-'16 Inch Periorations �t�R intt�R?rfc.rat=o�; <br /> ftip�Diameier(inr_hes) Fe�-f�ratian Spz�-im� Fip�Dsameter�fnches} <br /> F-�arati�n Sp�cng IF�«t1 - <br /> i 11: 1:: '[ s` (reFt) 1 t5�: 1�: 2 ? <br /> 2 12 18 26 4ir 81 2 21 ?� � 14 149 <br /> Zt< 12 1? d4 4�� $£� 2�� 2r� 30 41 59 135 <br /> 3 12 96 22 31 IS 3 20 29 38 64 12S <br /> �• Total Number of Perforations equals the Number of Perforotions per Latero( (Line 6)muttiplied by the Number of <br /> Perforoted Laterals (�ine 1). <br /> 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended va(ue is 4-10 ft z per perforotion. Pef'�°"°^°'��"•��,�"", <br /> Does not a ( to At-Grades Per(oratbn Otame[er <br /> PP Y Hesa�«� - <br /> '�8 �e ��li ��� <br /> Bed Area = Bed Width (ft)X Bed Length (ft) � <br /> 1.0' a.16 0.47 0.56 0.7i <br /> 1,5 0.22 0-51 0.69 0.9 <br /> 10 ft x 63 ft = 630 ftZ =.o° 0.26 0.59 0.� ,.o. <br /> 2.5 0.29 O_65 0.89 1.17 <br /> 3.0 0.32 0.72 0.98 1.2H <br /> Square Foot per Perforation =Bed Area divided by the Tota(Number of Perforations (Line 7). a.o 0.3� o.ea �.,3 ,.4� <br /> SA` O.d1 0.91 7.26 1.65 <br /> Pvellirrv5 wi[h 7/16 inc�to 1/-0 irch <br /> 630 ftZ = 63 perforations = 10.0 ftZ/perforations '`°°` vertoratiom <br /> Dvrelli�wi[h 1/d irrch peAoratiorrs <br /> 2�eet Otherr,IaEli:hmenlSandNS?Sv�th3/16 <br /> 9. Setect Minimum Average Head: 1.0 ft inch�0 1/4 inch peRoratiorc <br /> 5 feet �her estabiishn;ents and u.575 with i 78 inch <br /> pC'(OldL10�5 <br /> 10. Select Perforation Dischorge (GPM)based on Table III: 0.56 GPM per Perforation <br /> �1• Determine required F(ow Rate by multiplying the Tota(Number of Perforotions (Line 7)by the Perforation Discharge (Line 10). <br />
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