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2014-00827 - septic mound system
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75 Bayside Trail - 06-117-23-22-0030
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2014-00827 - septic mound system
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Last modified
8/22/2023 5:25:18 PM
Creation date
1/15/2016 12:55:23 PM
Metadata
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Template:
x Address Old
House Number
75
Street Name
Bayside
Street Type
Trail
Address
75 Bayside Tr
Document Type
Septic
PIN
0611723220030
Supplemental fields
ProcessedPID
Updated
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OSTP Pressure Distri ution <br /> Minnesota Pollution UNIVERSITY <br /> Desi n Workshe t ��;,: -�` <br /> Control A enc � OF 1VII NNESOTA : -,J,�,\�; <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Laterals in rystem/zone: � --- -- <br /> (2 feet is minimum and 3 feet is maximum spacing) '���"���°'���• ����- <br /> � ;:. ..: ..' -__ _ Y _ <br /> 2. Select Perforation Spacing: 3.0 f '� ' ` ��'s � ,��� - -` <br /> �,,. „�� <br /> Mini�nu�n ` <br /> .'t>�•�Inr.i��o��ti.1i.���.�1 i':��i.�r� 1"2..of rock -�-._12� <br /> 3. Select Perforation Diameter Size 7/32 � _ _ <br /> C+"uf�u�.k <br /> 4. Length of Loterols =Media Bed Length-2 Feet. o«f��.,����,z;:��,�,:�,.-,�,�,: �P�,o.�=,�„��.,�„�,:� , <br /> 63 - 2ft = 61 ft Perforation ca not be c(oser then '!foot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Lat ra(s (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft - 3 ft = 20 Spaces <br /> 6. Number of Perforations per Latera( is equal to 1.0 plus the Number of P rforatron Spaces (Line 5). <br /> PerforQtions Per Lateral = 20 Spaces + � = 21 Perfs. Per Lateral <br /> Check toble be(ow to verify the number of perforations per(atera(guar ntees less than Q 10%discharge variation. The value is <br /> dou6le if the a center manifo(d is used. <br /> Maximum Number�f Perfosations Per Lateral to Gua ante?t:1�l�e D'escharge Variak±cr� <br /> :�°Inch F ' °tet�c'''`' 7/32 Int�Ferferations <br /> �e�farat:�i�Spac;ng IFeat) �F°Cnamet-rr{inchesi Perfm ation Sp�ing Fipz C►iamefer(�nchr} <br /> � ".•: tt;� 2 3 4Fc-Pt1 1 tus t>� 3 3 <br /> 7 10 13 18 3Q 60 2 11 ib Z! 34 68 <br /> 2�� & t2 tb 28 54 2%� 10 1� 20 32 b� <br /> 3 R t2 ib 25 52 3 4 1� 99 30 tx? <br /> �'l6 inch Ferforations t;`8 Inch Pertoratiar�s <br /> Pipe Oiame±er il�xh�s) pesfo Non 5 Pi D�ame�er(6nches) <br /> Pe�arat�n Spac-ng ife?tl �"� � <br /> . 1�: 1�: 2 3 (Feetl 1 14: ti; 2 ? <br /> 2 12 i8 2b �#6 87 2 21 33 4� 74 14� <br /> _'" 12 17 2� � 80 2: 24 3t3 4i b4 135 <br /> '� !2 15 22 37 75 3 2Q 29 �8 b4 123 <br /> �• Total Number of Perforations equats the Number of Perforations per Lat rol (Line 6)multiplied by the Number of <br /> PerforQted Laterols (Line 1). <br /> 21 Perf. Per Lateral X ��Number of Pert. aterals = 63 Total Number of Perf. <br /> _ . _ _ <br /> 8. Catculate the Square feet per Perforation. Recommended value is 4-f0 f 1 per perforation. P��°n"onD�^•�s����, <br /> Does not apply to At-Grades I Pcrtoratlon Diametor <br /> Mead(!t) <br /> ��a '/. '/�t ,/. <br /> Bed Area = Bed Width(ft)X Bed Length (ft) <br /> 1.0' 0.18 O.sl 0.56 0.76 <br /> 7.5 0.22 0.51 0.69 0.9 <br /> 10 ft x 63 ft = 630 ftZ Z.o° °.26 0.59 0.� ,.o• <br /> 2.5 0.29 0.65 0.89 �.77 <br /> I.O O.JI 0.72 0.98 1.ZB <br /> Square Foot per Perforation =Bed Area divided by the Tota(Number of rjorations (Line 7). =o o.=� o.e� ,.,3 ,.,, <br /> 5.0` 0.41 0.93 1.26 1.65 <br /> 630 ftz - 63 rforations = z ,f�� ��e�������h;,�6����a,,.;Kh <br /> Pe 10.0 ft /perforations Pp�o�a�p�s <br /> U�:eqings with t/B inch peAoratbre <br /> 9. Select Minimum Average Head: 1.0 ft =��� a�r escaWishments and NSTS wi[h 3lib <br /> inch[0 7�4 inch perforaciom <br /> S��, O:her eyta0lisnments and NSTS wi[h 1/8 i�ch <br /> peAo.atwln <br /> 10. Select Perforation Discharge (GPM)based on Tabte III: 0.56 GPM per Perforation <br /> �1• Determine required Flow Rate by multiplying the Totol Number of Perfor ions (Line 7)by the Perforotion Drscharge (Line 10). <br />
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