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�.,�• a �� � . • ; to tea. �c <br />A. Determine pump capacity: <br />Gravity Distribution <br />1. Minimum suggested is 600 gallons per hour (10 gpm) to stay ahead of <br />water use rate. <br />2. Maximum suggested for delivery to a drop box of a home system is 2,700 <br />gallons per hour (45 gpm) to prevent build-up of pressure in drop box. <br />Pressure Distibution 3 <br />3. a. Select number of perforated laterals <br />b. Select perforation spacing a 3 feet <br />c. • Su�ct 2 fL from the layer length. <br />y-�- 2 fL s Y <br />�feel <br />d. Determine the number of spaces between perforations. <br />Length perf. spacing - W fL * 3 ft. - _6 spaces <br />e. L_ spaces + i = /_ perforations/lateral <br />f. Multiply perforations per lateral by number of laterals to <br />t t total number of perforations. t,WL x Q7 r� perforations. <br />g. x gwr 38 Spm, <br />SELECTED PUMP CAPACrrY 3 S gpm <br />B. Determine head requirements: <br />1. Elevation difference between pump and point of discharge. <br />_feet <br />2. if pumping to a pressure distribution system, five feet for pressure <br />required at manifold if gravity system, zero. <br />S feet <br />5. Friction loss <br />a. Enter friction loss table with gpm and pipe diameter. <br />Read friction loss in feet per 100 feet from table. <br />F.L.- 3,W fL/100 (t of pipe woe ?.O'' AWC <br />b. Determine total pipe length from pump to discharge <br />potnL Add 25 percent to pipe length for fitting <br />loss, or use a fitting loss chart. Equivalent pipe <br />length -1.25 times pipe length= <br />�VO x 1.25 - SG feet <br />c. Calculate total friction toss by multiplying <br />friction Ioss in ft/100 ft by equivalent pipe length. <br />Total friction loss - 2 - V/ x _J-.0 loo. A 2 feet <br />4. Total head required is the sum of elevation difference, <br />special head requirements, and total friction loss. <br />6 + S + 1.2 <br />(1) W (3d <br />TOTAL HEAD /2•. feet <br />G Pimp selection <br />1. A pump must be selected to deliver at least <br />P gpm .(Step A) with at least _,ZZ, feet of total head (Step B). <br />F-17 <br />DO PCFWORATt' 1 Or • INDWORATO LATEU-1 <br />C~ Coal, <br />tar <br />dar of b r . carr to ra- <br />r/ tical Lora � �i iti. M �, .r.......� <br />wHooam%bobo abboa4 <br />yi Y lW get. to" <br />V Ara Lora <br />Coma Same WW <br />R.qubad Pwhrad= • <br />!n aaltaru pmmirwta <br />ar <br />Disc <br />04160 <br />0.69 <br />0.20 <br />1.0a <br />0.56. <br />0.:4 <br />2.Ob <br />0.80. <br />1.04 <br />a. Use for single family homes <br />b. Use for all other applications <br />Pipe L cn8th <br />Point of D'Lscharg <br />Ej;:-�Etvttdan Diffarnce.. <br />P <br />F -18b <br />.. 13 inch 2.0 inch Minch <br />am r wmlr.p.10ondpips <br />10 <br />0.69 <br />0.20 <br />12 <br />0.96 <br />0.28 <br />14 <br />1.28 <br />038 <br />16 <br />1.63 <br />0.48 <br />18 <br />203 <br />0.60 <br />20 <br />Z.47 <br />0.73 <br />0.11 <br />25 <br />3.73 <br />1.11 <br />0.16 <br />30 <br />533 <br />1.55 <br />0.23 <br />35 <br />7.90 <br />Z06- <br />030 <br />40 <br />1I.07 <br />L64 <br />039 <br />45 <br />14.73 <br />3.28 <br />0.48 <br />so <br />3.99 <br />0.58 <br />55 <br />4.76 <br />0.70 <br />60 <br />5.60 <br />0.82 <br />