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31 <br />G. DOWNSLOPE DUM WIDTH <br />I. If landslope is 3% or more, subtract rock layer width from <br />adsorption width to obtain minimum downslope dike toe <br />, 20 ft • L_ ft- _/0 feet <br />2.' Calculate Minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer. Separation L S feet <br />b. Multiply rock layer width by landslope <br />to determine drop in elevation; <br />Slope Difference ssoorotloh <br />/a x _Y 90 + 100 = 0• Y feet uos►tot width <br />c. Add depth of dean sand for separation (2a) tett <br />at upslope edge, depth of rock layer (1 foot) to depth of <br />cover (1 foot) to find the mound height at the upslope edge <br />of rock layer, <br />1,Sift+Ift+Ift=,Z.�; feet <br />d. Enter table with landslope and upslope dike ratio'. <br />Select dike multiplier )f <br />e. Multiply dike multiplier by upslope mound height <br />to find upslope dike width:._ VS x -2.5— = /1.1 feet <br />f. Add depth of dean sand for slope difference (2b) at <br />downslope edge, to the mound height at the upslope edge <br />of rock layer (20 to find the downslope height; <br />...5 ft+eft=,,tfeet <br />g. Enter table with landslope and downslope dike ratio. <br />Select dike multiplier of V. 7 6 <br />It. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 9.9 x JL7L = /gO. 6 feet <br />i. Compare the values of step G.1 and Step G.2h Select the <br />greater of the two values as the downslope dike width; <br />feeter— <br />I toot Cove <br />t't••t RtZtt.d <br />rut . <br />Slope Difference �. <br />Rocr old width <br />feet °ownsloot width <br />tett <br />j. Total mound width is the sum of toot .. <br />upslope dike (G.2e) width plus rock <br />layer width (D.2) plus "s u••i::• M1list <br />downslope dike width(G.2i); `e" a�.. <br />/2. / ft + /a ft + /8. 6 ft = o• 7 feet <br />k. Total mound length is the sum of °i"�"`N•f.sta <br />upslope dike width (G.2e) plus rock layer <br />length (D3) plus upslope dike widtah (G.2e); <br />[.- ...�. Z.L Z� <br />Z. / ft + S ft + 2 ft = 2 feet "I� • <br />Tttel letdtt <br />31 <br />u <br />W r <br />fa <br />7:1 <br />u <br />u <br />-r$-1 ` <br />61 <br />7:1 <br />a <br />• <br />o � <br />38 <br />ao <br />sa <br />fro <br />7J <br />1.8 <br />ao <br />to <br />u <br />sa <br />N <br />1 <br />301 <br />u7 <br />LN <br />•io <br />Til <br />2.111 <br />3i <br />4.76 <br />Lff <br />am <br />741 <br />3 <br />311 <br />&A <br />a% <br />as <br />Lu <br />3Jt <br />in <br />aft <br />363• <br />ltI <br />L7t <br />alt <br />uo <br />3 <br />3M <br />aft <br />Lao <br />lit <br />am <br />o77 <br />371 <br />lY <br />to <br />is <br />aft <br />4.17 <br />i+a <br />alt <br />Lff <br />aol <br />• <br />3a <br />ax <br />am <br />as <br />a0 <br />Tit <br />a77 <br />167f <br />tY <br />331 <br />lOD <br />a+i <br />L» <br />1171 <br />1 <br />33 3 <br />3A <br />La <br />7.1• <br />did <br />UN <br />236 <br />Lal <br />1•l <br />an <br />l0 <br />4" <br />36.1 <br />L13 <br />f <br />7 <br />3A0 <br />1156 <br />7Y <br />1636 <br />Ulf <br />34 <br />3.13 <br />3.70 <br />as <br />a0 <br />aft <br />•N <br />d <br />LA <br />LN <br />to <br />lssm <br />ups <br />less <br />US <br />236 <br />:um <br />M <br />u <br />u <br />•� <br />• <br />au <br />to! <br />tLad <br />7331 <br />Sit <br />� <br />•r <br />•if <br />11 <br />w <br />af7 <br />7u <br />tut <br />l� <br />30,41 <br />i <br />Sao <br />7US 7s <br />Lin <br />am <br />s.d0 <br />40 <br />I= <br />731 <br />3711 <br />3u <br />12 <br />w <br />fes <br />