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l3. uUVVNbLUM ul2\1-VV r -1►-i <br />I. if landslope is 3% or more, subtract rock layer width from <br />adsorption width to obtain minimum downslope dike toe for <br />absorption: <br />ft -eft=_ 'L feet <br />2. Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation � , U feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference limp" <br />) 0 x _ - % + 100 = _L feet ��-- <br />c. Add depth of clean sand depth of clean sand for +i~l- oA- �+�-- <br />separation at upslope edge (2a) to depth of rock lay<°r to IA -#W <br />rock depth and the depth of cover to find the total niuund <br />height at upslope edge of rock layer; <br />a.0 ft+ 1 ft+1 ft=_LLQ feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of �.115 <br />e. Multiply dike multiplier by upslope mound hs-i-Im <br />to get upslope dike width: 4 .0 x 3,n = !'S ret <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height <br />H , u +, Le - 4 • (, feet <br />g. Enter table on page bottom with landslope and <br />downslope dike ratio. <br />Select dike multiplier of a <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 4 . L x S zj = _k!4L_ feet <br />i. Cor�-are the values of sten " 1 and Step G -2-h. Select the <br />gr. .er of the two value. ! downslope dike width; <br />�-�1 feet <br />j. Total mound u idth is the sum of upslope dike <br />width plus rock layer width plus dowr.s!ope <br />dike width; <br />ft + I 0 ft + ft UP,1- <br />k. Total mound length is the sum of upslope <br />dike ,-!idth plus rock layer length plus <br />upslope dike width; <br />- �y--- <br />ft i• -_� ��-- f t + L _.- ft = a1 `(-- feet <br />7 L4S -{ <br />�I <br />Q6 <br />11 <br />LI <br />- M„: a{capc <br />k1 <br />6;1 <br />7:1 <br />11 <br />L1 <br />S.1 <br />kt <br />7:1 <br />SA <br />1 dem <br />0 <br />JO <br />1.0 <br />5_0 <br />10 <br />74 <br />30 <br />1.0 <br />S.0 <br />60 <br />7.0 <br />10 <br />1 <br />JA <br />6.17 <br />536 <br />6.3t <br />79,1 <br />291 <br />3 a <br />176 <br />5.Y <br />651 <br />7AI <br />2 <br />1.19 <br />615 <br />$36 <br />6.82 <br />614 <br />263 <br />1110 <br />I34 <br />S36 <br />111 <br />6.90 <br />3 <br />330 <br />131 <br />S06 <br />731 <br />666357 <br />43S <br />S01 <br />5.79 <br />6AS <br />/ <br />341 <br />6.:6 <br />62S <br />7►9 <br />+'.72 <br />:nr <br />34i <br />•..7 <br />aU <br />S <br />3.i3 <br />Soo <br />667 <br />57 <br />1: <br />: nl <br />3 33 <br />100 <br />: /J <br />S 19 <br />5.71 <br />6 <br />116 <br />526 <br />7.11 <br />93t <br />1207 <br />251 <br />3.23 <br />3 L <br />Il./.9. <br />511 <br />7 <br />310 <br />6.56 <br />LI$ <br />1L . <br />1313 <br />1" <br />3.12 <br />x.70 <br />6 n <br />1.70 <br />5.11 <br />1 <br />3.9S <br />S# <br />W <br />1156 <br />15-91 <br />212 <br />303 <br />1S7 <br />/OS <br />/.M <br />/JJ) <br />9 <br />1,11 <br />425 <br />9.00 <br />13.06 <br />1192 <br />2 36 <br />2.91 <br />3.6S <br />3.90 <br />130 <br />IAS <br />10 <br />12q <br />467 <br />100 <br />15A0 <br />2333 <br />231 <br />216 <br />31) <br />? 73 <br />/.1. <br />6.11 <br />11 <br />446 <br />7.11 <br />11 11 <br />17LS <br />3013 <br />226 <br />270 <br />3.23 <br />341 <br />3.95 <br />126 <br />12 <br />4b9 <br />7.N <br />1251 <br />1143 <br />4375 <br />721 <br />770 <br />312 <br />349 <br />380 <br />LO <br />