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1993-12-21 Septic System Design Report
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1993-12-21 Septic System Design Report
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Last modified
4/16/2025 4:20:40 PM
Creation date
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x Address Old
House Number
2760
Street Name
Countryside
Street Type
Drive
Street Direction
West
Address
2760 Countryside Drive West
PIN
04-117-23-12-0011
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated -) s o gpd (seepages D-7 or I-3, 4, 5) <br />or measured gpd x 1.5 = — <br />B. SEPTIC TANK LIQUID VOLUMES <br />J -; goc3gallons (see pages 3 or C-5; <br />C. SOILS (refer to s.:e evaluation) <br />1. Depth to restricting layer = 1 a �v v' inches <br />2. Depth of percolation tests = 1 a " inches <br />3 Percolation rate q ,r 1 mpi <br />Land slope % <br />13n1rrcd sewSe Flows In Galium per ay <br />(9d) <br />c.Ne4per <br />'!os <br />•, <br />R201001ef <br />��n <br />M=m <br />main Mrn a 1 <br />co.n/ save <br />-- <br />of <br />iypc I <br />Type II <br />7ypc III <br />IAO <br />N*oomt <br />"M said» <br />*A <br />2.00 <br />fV <br />2 <br />306 <br />223 <br />ISO <br />Ll:: <br />3 <br />456 <br />300 <br />219 <br />M <br />4 <br />600 <br />375 <br />256 <br />r <br />5 <br />75C <br />450 <br />2W <br />6 <br />900 <br />S2S <br />332 <br />Tr 1. <br />7 <br />1050 <br />600 <br />370 <br />Ga <br />S <br />1200 1 <br />675 <br />1 401 <br />�+... <br />S,V Ur T.ab Cap" rim In Nor <br />\rakrrd <br />al�►./.;r4 <br />Lq.Wr7w+Y.Y <br />Bdn.r. <br />c4rr.ry <br />pbw d -F -W <br />1 w kw <br />750 <br />1125 <br />3:4 <br />1000 <br />llw <br />4�6 <br />13W <br />2270 <br />7.4 ar 1 <br />30M <br />300D <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />' 'J gpd x 0.8.3 sq. ft./gpd = so. ft -i )o`er (r,%`+" <br />2. Select uridth of rock layer 00 feet or less) _ 16 ft. <br />3. Length of rock layer • Area + Width = <br />LYLf sq. ft. + Zo ft.= coV ft. <br />E. ROCK VOLUME <br />I. Multiply rock area by rock depth to get cubic feet of rock; <br />� sq. ft. x lx,� ft. - _v)1fS cu. ft. <br />2 Divide cu. ft. by 27 cu. ft./C?. --rd. to get cubic yards; <br />r�&cu. ft. + 27 - __,-o ' _ cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />'D n cu. yd. x 1.4 ton/cu. yd. _ 1 -i? tons. <br />F. ADSORP 1ON WIDTH L01I w 1 <br />1. Percolation rate in top 12 inches of soil is mpi <br />2. Select allowable soil load in rate from table on page E-; <br />.0 gpd/ft2 <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/W4- . u, gpd /ft2= _ a . l.? <br />Check this value on page E -I6. <br />4. Multiply adsorption width'ratio by rock layer width to get <br />required adsorption width; <br />I a,x -)L.1) ft s ft <br />i <br />?�}Tfh?tJi��.'ZT�:tlilt2lT1:tl <br />Abp W;em Width swngTubp: <br />r.Robd=fir. <br />� <br />wnt Soil Tea <br />c.Ne4per <br />'!os <br />•, <br />R201001ef <br />��n <br />M=m <br />main Mrn a 1 <br />co.n/ save <br />-- <br />— <br />W a s <br />940/ <br />1.30 <br />IAO <br />0.1 IDS N <br />"M said» <br />*A <br />2.00 <br />f <br />I2Ao <br />»1330 <br />Ll:: <br />l0 <br />310043 <br />31M 1. Ims <br />M <br />7.40 <br />46 <br />Lasso021 <br />OAS <br />2S? <br />ti01.120 <br />500 <br />
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