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1. If landslope is 2.9 percent or less, basal width includes both the <br />upslope and downslope dike widths, <br />P1 <br />Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation / . _2. I feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference <br />jerence <br />/0 x 2 %+100= . '- feet <br />c. Add depth of clean sand depth of clean sand for s>*. <br />separation at upslope edge (2a) to depth of rock layer to... <br />rock depth and the depth of cover io find the total mound,.... <br />height at upslope edge of rock layer; <br />,1.Zft+ 1ft+1ft= 2.7 feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of 3.1) cJ <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 1. -2- x =1Z feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height 3.'z + , -L = <.0 feet <br />g. Enter table on page E-18 with landslope and downslope <br />dike ratio. Select dike multiplier of 4 .2 5' <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: z . y x Ll .3i = _L_d_ feet <br />L Mininmum mound width is the sum of upslope dike <br />width plus rock layer width plus downslope dike %vidth; <br />I- ft + ) Q_ ft + i ft= 12 feet Rock Bcd'YVid1i,"1a` <br />j. Subtract the Minimum width G.i from the Absorption <br />width FA to find the Additional Do<<•nslope required far <br />Absorption <br />�^ ft - ft = - i ;: feet �P'P <br />k. Add the Additional Downslope required for Absorption <br />to the downslope dike width and recalulate the Total <br />Mound Width which is is the sum of upslope dike <br />width plus -ock layer width plus downslope dike width <br />�a ft+eft+YS� ft =2feet <br />1. Total mound length is the sum of upslope dike width <br />plus rock layer length plus upslope dike width; <br />),I ft + _ ft + _Jam_ ft = '�-L_ feet <br />1 S 4 !c -4 I ;; C7 V <br />---Tohl unth 'f 2 - -� <br />9� <br />kl <br />a 1 <br />kUb"Milope <br />41 <br />7A <br />2 1 <br />4 1 <br />°P� <br />A <br />[1 <br />7:1 <br />•:1 <br />L dopy <br />0 <br />3A <br />4.0 <br />SA <br />40 <br />7.0 <br />3.0 <br />40 <br />so <br />60 <br />7.0 <br />610 <br />1 <br />3D <br />6.17 <br />516 <br />63 <br />7.33 <br />291 <br />36t <br />474 <br />5K <br />634 <br />7A1 <br />3.19 <br />556 <br />6+2 <br />616 <br />26t <br />::; <br />536 <br />614 <br />690 <br />? <br />377 <br />651 <br />sM <br />C3, <br />nS.. <br />7 "_ <br />ci <br />>�67 <br />FL <br />4 <br />3A1 <br />4.76 <br />125 <br />:.6, <br />9 <br />2.' <br />3 :� <br />4!7 <br />4 bf <br />5.K <br />6.06 <br />S <br />333 <br />S.00 <br />167 <br />657 <br />1077 <br />261 <br />333 <br />4 W <br />1.62 <br />5.19 <br />S.71 <br />6 <br />3Ai <br />316 <br />7.16 <br />9.36 <br />12.07 <br />236 <br />3.23 <br />3.65 <br />6.11 <br />6.93 <br />SAI <br />310 <br />S_% <br />7A o <br />,031 <br />1373 <br />246 <br />3.12 <br />3.70 <br />4.23 <br />170 <br />5.13 <br />t <br />3.95 <br />s1{ <br />633 <br />1134 <br />Is.$1 <br />2.42 <br />303 <br />357 <br />4.0S <br />4.0 <br />4M <br />9 <br />4.11 <br />625 <br />909 <br />13.04 <br />16,92 <br />2 M <br />2 94 <br />3.45 <br />3.90 <br />4.30 <br />46S <br />10 <br />429 <br />6.47 <br />WA <br />15.00 <br />2333 <br />231 <br />2S6 <br />131 <br />3.75 <br />4.12 <br />4.44 <br />11 <br />4A6 <br />7.14 <br />11.11 <br />17AS <br />3^ 43 <br />2 26 <br />2 7e <br />3 :3 <br />3.61 <br />3.95 <br />426 <br />12 <br />4M710 <br />1230 <br />21 43 <br />43.75 <br />2 21 <br />2.70 <br />3A <br />3.49 <br />390 <br />4A6 <br />