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1993-12-10 Septic System Design Plan
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1993-12-10 Septic System Design Plan
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Last modified
4/16/2025 10:26:03 AM
Creation date
4/16/2025 10:17:37 AM
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x Address Old
House Number
2700
Street Name
Countryside
Street Type
Drive
Street Direction
West
Address
2700 Countyrside Drive West
PIN
0411723120012
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated 0-<0 gpd (seepages D-7 or 1-3,4,5) <br />or measured - gpd x 1.5 = <br />B. SEPTIC TANK LIQUID VOLUMES <br />I -, I ije- - gallons (see pages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = a: inches <br />2. Depth of percolation tests = " inches <br />3. Percolation rate 1 a, . 2, mpi <br />4. Land slope Q % <br />Eseksmsed Sewage Flows N CaBma per day <br />(aped) <br />Numeber <br />O <br />7yps t <br />Type" <br />i"M III <br />7ytrt <br />1ledr o s <br />&I as <br />Said <br />I.7o <br />1:Oo <br />2 <br />300 <br />225 <br />lao <br />iw13 <br />i�i� l�ia�� <br />450 <br />300 <br />218 <br />600 <br />376 <br />256 <br />tr <br />5 <br />750 <br />Oso <br />294�' <br />s m <br />6 <br />900 <br />526 <br />332 <br />yI�a' <br />7 <br />1050 <br />600 <br />370 <br />a.4 <br />■ <br />a <br />1200 <br />67S <br />408 <br />.r.. <br />a.p& Tmb Cgwlakm h peva. <br />L�r►ya.r�d <br />iarawar <br />C�aciLip <br />l ar rr <br />Tao <br />1115 <br />3. . <br />Imo <br />two <br />I o • <br />I= <br />u10 <br />7.9 W 9 <br />�Oa <br />30N <br />awrf <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer. Daily Flow x 0.83 = <br />NSy gpd x 0.83 sq. ft./ <br />gpd = sq. p <br />2. Select width of rock layer (10 feet or less) _ /O ft. <br />3. Length of rock layer : Area + Width = <br />6, V q sq. ft. + 10 ft. = 1, 1 ft. <br />E. ROCK VOLUME <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />. {r sq. ft. x LAI- ft. _ -JL5� cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />w_/ cu. ft. + 27 = ;, I cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />d �i cu. yd. x 1.4 ton/cu. yd. _ - i!� tons. <br />F. ADSORPTION WIDTH LV-AL� L.o t-% <br />1. Percolation rate in top 12 inches of soil is j mpi <br />2. Select allowable soil loading rate from table on page E <br />tl gpd/ft2 <br />3. Calculate adsorption width ratio by dividing nock layer <br />loading rate of 1.20 gpd/fF by allowable soil loading rate;. <br />1.20 gpd/ftp 4- �� Spd/ft2 _ <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption . width; <br />_1,2xio ft=01.7 ft <br />aw.1plim wIft stars a TANI <br />real"In am <br />1. <br />• W (� <br />a.11tfaaw <br />i 11:111,11M <br />C�ar <br />gawMe <br />Aw:� <br />M R84 Law <br />wwo <br />Aw. w a 1 a <br />Ceara low <br />-- <br />&I as <br />Said <br />I.7o <br />1:Oo <br />0.110300 <br />IN <br />iw13 <br />i�i� l�ia�� <br />a°m <br />7s <br />152 <br />0629 <br />2.40 <br />cfl�rL <br />s m <br />Go ua <br />a4r <br />o <br />K <br />-- <br />
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