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G. DOWNSLOPE DIKE W1D•1 r► <br />1. If landslope is 3% or more, subtract rock layer width from <br />adsorption width to obtain minimum downslope dike toe for <br />absorption: <br />.1L. ft- Y_ft= feet <br />2. Calculate minimum mound size based on geometery: <br />a. Determine depth of clean sand fill at upslope edge of rock <br />layer: Separation 1 • o feet <br />b. Multiply rock layer width by landslope to determine drop <br />in elevation; Slope Difference <br />x % + 100 feet <br />c. Add depth of clean sand depth of clean sand for tj' �• L-•- 26•• a--•• <br />separation at upslope edge (2a) to depth of rock layer to <br />rock depth and the depth of cover to find the total mound W.66 <br />height at upslope edge of rock layer; <br />1.0 ft + 1 ft + 1 ft = -. y feet <br />d. Enter table on page bottom with landslope and upslope <br />dike ratio. Select dike multiplier of <br />e. Multiply dike multiplier by upslope mound height <br />to get upslope dike width: 3 • o x ; = lo feet <br />f. Add the depth of slope difference (2b) to the upslope <br />height to get the downslope height <br />3.p +. (o_= 3 . (. feet <br />g. Enter table on page bottom with landslope and <br />downslope dike ratio. <br />Select dike multiplier of t. <br />h. Multiply dike multiplier by downslope mound height <br />to get downslope dike width: 3. V x S.zu = )'It feet <br />L Compare the values of step G.1 and Step G.2.h. Select the <br />greater of the two values as the downslope dike width; <br />/9 feet <br />j. Total mound width is the sum of upslope dike HOC i%Q'd '_j�`WW <br />width plus rock layer width plus c'.r. wnslope <br />dike width; s: <br />_ _ `ip:wavft+1Qft+ ft=M.op+=.� <br />k. Total mound length is the sum of upslope <br />dike width <br />lus rock layer length plus <br />P Y S <br />upslope dike width; <br />- <br />_ Jo ft + ��_ ft + feet L )'.7a:l..a•!.___ <br />Zl <br />11 <br />4:1 <br />rwns op.:ps <br />5:1 <br />L1 <br />7:1 <br />3:1 <br />ll <br />oN <br />5:1 <br />kl <br />7:1 <br />8:1 <br />16 Nope <br />0 <br />30 <br />40 <br />5.0 <br />60 <br />70 <br />30 <br />4.0 <br />SO <br />60 <br />7.0 <br />{.0 <br />1 <br />30 <br />4.17 <br />526 <br />h35 <br />733 <br />291 <br />3.65 <br />475 <br />$.66 <br />656 <br />741 <br />2 <br />319 <br />1.35 <br />556 <br />5; <br />614 <br />2 s) <br />3. 0 <br />4.4 <br />5.36 <br />614 <br />6 v0 <br />1 <br />).30 <br />'4 <br />5.191 <br />7I) <br />�.6 <br />357 <br />4); <br />s04 <br />;-9 <br />64i <br />4 <br />44: <br />623 <br />2b <br />34t <br />4:7 <br />414 <br />C4« <br />6:'.• <br />353 <br />ea <br />wl <br />7 4?. <br />07 <br />24 <br />2:3" <br />3h; <br />441 <br />4:3 <br />$41 <br />7 <br />) {[I <br />^S.fs <br />764 <br />10.;. <br />13 73 <br />'?.4{ <br />712 <br />3.M <br />4 73 <br />4 70 <br />S13 <br />39S <br />S.Y <br />{33 <br />1156 <br />15.91 <br />2.12 <br />IM <br />357 <br />4 05 <br />449 <br />4&9 <br />9 <br />4.11 <br />X25 <br />9.09 <br />13 04 <br />16.92 <br />236 <br />2,94 <br />3.43 <br />3.9U <br />630 <br />4 65 <br />10 <br />4-19 <br />6.67 <br />10.0 <br />1500 <br />2737 <br />211 <br />2.116 <br />333 <br />175 <br />412 <br />11 <br />444 <br />7.14 <br />:1.11 <br />lit <br />1`t) <br />226 <br />279 <br />323 <br />361 <br />3v5 <br />426 <br />:2 <br />1.69 <br />7.49 <br />1230 <br />2' 4 t <br />.. <br />::1 <br />2 70 <br />3 12 <br />3 44 <br />1 ±0 <br />4 OR <br />