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1993-12-19 Septic System Design Report
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1993-12-19 Septic System Design Report
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Last modified
4/10/2025 1:52:54 PM
Creation date
4/10/2025 1:46:02 PM
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x Address Old
House Number
2655
Street Name
Countryside
Street Type
Drive
Street Direction
West
Address
2655 Countryside Drive West
PIN
0411723130006
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MOUND DESIGN WORKSHEET <br />(For Flows up to 1200 gpd) <br />A. FLOW <br />Estimated 0-<0 gpd (seepages D-7 or 1-3,4,S) <br />or measured - gpd x 1.5 = -- <br />B. SEPTIC TANK LIQUID VOLUlt4ES <br />/-);L<-)" I ,_ gallons (seepages C-3 or C-5) <br />C. SOILS (refer to site evaluation) <br />1. Depth to restricting layer = 1 ,�t =cc ' inches``�f <br />2. Depth of percolation tests = 1 inches <br />3. Percolatio .ate -5�� mpi <br />4. Land slope 6 % <br />Estimalod Sewage Flows iw Gallufts par Jay <br />(gpd) <br />. wnbor <br />Ra to of <br />Abaspsiott width <br />p Rock (ay0 <br />wom <br />Ratan Ibaft 0. t 0 <br />Coro So" <br />Of <br />Type i <br />Type 11 <br />Type III <br />T�pe <br />ncst�t <br />Rine Saftd'• <br />0.60 <br />LM <br />v <br />2 <br />300 <br />225 <br />Igo <br />t nat7t <br />3 <br />450 <br />300 <br />211 <br />WS <br />4 <br />600 <br />375 <br />256 <br />'at" <br />5 <br />750 <br />450 <br />247 <br />a'n <br />6 <br />900 <br />525 <br />332 <br />Tir 1. <br />7 <br />1050 <br />600 <br />370 <br />mw <br />1 <br />1200 <br />673 <br />409 <br />errs <br />Soyl'c Tani C.P-Ai% In a•IL..• <br />1. <br />Ikdrwm• <br />Cum,.y <br />yv�.:y <br />...10J.Po.1sa <br />a t>ap: ,w..l <br />2 a kw <br />750 <br />1125 <br />fr4 <br />1010 <br />15x0 <br />4 s 6 <br />IfuD <br />2250 <br />7.1 in 9 <br />xW <br />7000 <br />D. ROCK LAYER DIMENSIONS <br />1. Multiply flow rate by 0.83 to obtain required area of rock <br />layer: Daily Flow x 0.83 = <br />r),<0 gpd ,. ' - --sq. ft. /gpd = a a sq. f t.-1 I r. <br />2. Select width of rocj;,wyer (10 feet or less) _ / ft. <br />3. Length of rock layer = Area + Width = <br />t,VL4 sq. ft. + 1_ ft.= re/ ft. <br />E. ROCK VOLUME <br />1. Multiply rock area by rock depth to get cubic feet of rock; <br />Gam. sq. ft. xo{ ft. = 2ts� cu. ft. <br />2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br />21j� cu. ft. + 27 = _3,? cu. yd. <br />3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br />-0 cu. yd. x 1.4 ton/cu. yd. _ 3je. tons. <br />F. ADSORPTION WIDTH /--L-A,-4 I -o xk rl <br />1. Percolation rate in top 12 inches of soil is !�- q mpi <br />2. Select allowable soil loading rate m table on page E-; <br />. ti ft= <br />3. Calculate adsorption width ratio by dividing rock layer <br />loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br />1.20 gpd/ft2+ '4S gpd/ft2= _ rad . <br />Check this value on page E-16. <br />4. Multiply adsorption width ratio by rock layer width to get <br />required adsorption width; <br />X p ft ft <br />�--- L.et7gth <br />Abnrpthm Width SiatMll Table <br />lOwcobdonitaft <br />ift Mil -es_ <br />Ittd (1V1►1J <br />SoU Te twe <br />Galbfta <br />par dry par <br />fgllaea f001 <br />Ra to of <br />Abaspsiott width <br />p Rock (ay0 <br />wom <br />Ratan Ibaft 0. t 0 <br />Coro So" <br />0.1465 <br />Sand <br />1.J0 <br />IAO <br />0.1 aft S as <br />Rine Saftd'• <br />0.60 <br />LM <br />6 * 13 <br />Sardy Man <br />0.79 <br />132 <br />16 a 30 <br />t nat7t <br />060 <br />200 <br />31 b 45 <br />Sib l.oatft <br />0.50 <br />2.40 <br />161060 <br />Clay a aftto <br />0.43 <br />2.67 <br />60 to 120 <br />Clay <br />0.24 <br />S.UU <br />slower daft <br />pay <br />12tH• <br />
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