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OSTP Pressure Distribution <br /> UNIVERSITY <br /> . � <br /> Min�esota Pollution Des�gn Worksheet OF MINNESOTA <br /> Control A enc �-''-�'" <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Loterals in system/zone: � --_ _ -- <br /> �„...�.,., �,,:.:,.�:�, <br /> (2 feet is minimum and 3 feet is maximum spacing) <br /> _ .:. _ ��. , <br /> 2. Select Perforation Spacing: 3.0 ft � ' s�'' � _ _ <br /> < . � <br /> Min�muin <br /> '/-'�����I�.�:�t������.�.��.���.cl�t'.��i.��i 1"�2"ol r�>ck •r „ .a <br /> 3. Setect Perforation Diameter Size 7/32 in _ _ <br /> C."c�l rwk <br /> 4. Length of Laterals =Media Bed Length-2 Feet. �.������.,�;�,,, �»:' "io n" rc�toc,ron;�.,nn�� �'co, <br /> 63 - 2ft = 61 ft Perforation can not be closer then 1 joot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Latera(s (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- �ft = 20 Spaces <br /> 6. Number of Perforations per Loteral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Latern( = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check toble below to verify the number of perforations per(ateral guarantees(ess than a 10%discharye voriotion. The va(ue is <br /> double if the a center manifold is used. <br /> Maximum Nurt�er of Fe��ations Fer L�eral to Guarantee<:tfl�e i�ischarge Variaro� <br /> `,(nth P QfeiG�15 7t32 Inc�Pe�feratio�s <br /> Pipe Diarrr�ier llnches) Perfaratiun Spacing Pip?Uameter(Inchesi <br /> Fe�farat:on Spaong iFeet? <br /> t il; i�: 1 3 IFe�etl 1 1�: 11: 1 3 <br /> 2 tt� 13 i� 30 60 2 11 16 2! 34 68 <br /> 2;". 8 12 t5 28 54 2�: 1Q 1�1 2C� 32 h4 <br /> 3 $ 12 ib 25 5't 3 9 14 19 30 6Q <br /> 3'16 lrt�h Perforatians 1'8 lnch Pe�fcrations <br /> F'ipe Diar►�ter tincEws) Perfaration Sp�cing Fipe tha!*�eter(inch�sl <br /> Pe�crai�o:�Spacn�(Feetl <br /> t 11: 1 t� 2 3 (Feetl i t� f tZ 2 3 <br /> 2 12 18 2b 46 87 2 2t 33 44 14 149 <br /> 2�� 12 17 1� 44 8n 2i: 24 3Q 4t b9 135 <br /> 3 12 16 12 37 75 � 2C 19 38 b4 12� <br /> 7- Total Number of PerJorations equals the Number of Perforations per Latera( (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> ___ _ __ _ <br /> 8. Catculate the Squore Feet per Perforation. Recommended value is 4-10 ftz per perforotion. °e`«•"°"°„`""�"`P"`� <br /> Does not app/y to At-Grades Hcad(tt) �rforatbn Dtamecer <br /> ,,a �,, , �,, <br /> Bed Area = Bed Width(ft)X Bed Length (ft) <br /> �,O' 0.18 O.it 0.56 0.71 <br /> 7.5 0.22 0.51 0.69 0.9 <br /> 10 ft x 63 ft = 630 ftZ =.°° °.� °.5' °.� ,.°` <br /> 2.5 0.29 0.65 D.89 1.17 <br /> 3.0 0.72 0.72 0.98 1.26 <br /> Square Foot per Perforation =Bed Area divided by the Tota!Number of Perforations (Line 7). 4.0 0.» 0.83 ,.,3 ,.°7 <br /> s.o` o.ai o.93 �.ze i.es <br /> � Z � Llvellir�with 31 t6 irKh[o t l�irch <br /> 630 ft 63 perforations = 10.0 ftZ/perforations '`�°` OCAO�a(i0M <br /> C�vrlling:wi[h 1/e inch peAora[cfc <br /> Zleet Otherr,[aMishmen[sand,vS75wich3/16 <br /> 9. Select Minimum Average Head: 1.� ft inch to 7/a inch DeRoratbn <br /> 5 Ittc a�e�`zcadisnments and Y575 wi;n t/B irxh <br /> perforations <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required Flow Rate by multiplying the Toto(Number of Perforations (Line 7)by the Perforotion Discharge (Line 10). <br />