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OSTP Pressure Distribution <br /> Minnesota Pollution UNIVERSITY _� - <br /> Design Worksheet OF IVIINNESOTA <br /> Control A enc - �``�;' <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Lotero(s in system/zone: � _--- ---- <br /> (2 feet is minimum ond 3 feet is maximum spacing) " �����" "� �'" _ _ <br /> _;, _ ,_ <br /> 2. Select Perforation Spacing: 3.0 ft ` � � 1z�'�' _ � <br /> � � <br /> M�����n�m <br /> 'Ja'f��•rio�:ation•..��:���•d 3'.���.�r� t`7.•of�ock 11" <br /> 3. Select Perforation Diameter Size 7/32 in _ _ <br /> G"uf�u�k <br /> 4. Length of Loterols =Media Bed Length -2 Feet. P<,f�,�.,,,�„s ,,, ,-,� P�„��,..,�,��,,U.,�„�,� ,, <br /> 63 - 2ft = 61 ft Perforation can not be c(oser then 1 Joot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Laterols (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- �ft = 20 Spaces <br /> 6. Number of Perforotions per Loteral is equai to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check tab(e below to verify the number of perforotions per fatera(guarantees less than a 10%discharge variation. The value is <br /> doubte if the a center manifold is used. <br /> Maximu�N�rt�er of Perfaations P�Lateral to Guarante�e�1U+ti Discharge Variaiion <br /> �i�,n P�tc�ra�a�s 1;311nch P?rforatians <br /> Pipe Qiameter(Irxhesl Fe�foratio�Sp3cing Pipo Cra�reter(lr�thes} <br /> Pe�foratinn Spacng IFr_�tl <br /> t 1S•: 11� r 3 (Feefi f lYs 1�� 2 3 <br /> i 10 13 18 30 60 2 11 16 21 34 6$ <br /> Z�^. � t2 16 28 54 2�: 1G 14 20 32 b� <br /> 3 8 i2 1b 25 52 3 9 14 19 30 64 <br /> 3i16 knch Perfora:ions 1 '8 Inch Petforattons <br /> Pipe Qiameter Ii�chesl Pe*foration Spacing Pipe DsameiEr(Inches! <br /> Pe�forat ry�SRac�ng IFeetl <br /> 1 1�� 1ti: I 3 (Feetl I 1�. 11: 2 ? <br /> Z 12 18 26 4b 87 2 21 33 �4 74 149 <br /> 2�2 12 17 24 44 80 1�`: 20 30 �tt 69 135 <br /> 3 12 15 2Z 37 75 3 20 29 38 54 128 <br /> 7• Total Number of Perforations equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of <br /> Perjorated Laterals (Line 1). <br /> 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Totat Number of Perf. <br /> ___ <br /> 8. Calculate the Square Feet per Perforation. Recommended velue is 4-10 Jt Z per perforation. P�``°""°"°iscAa�jG°"> <br /> Perforatlon Dlamctcr <br /> Does not apply to At-Grades Head Itq , a ,� -�_ ,� <br /> i <br /> Bed Area = Bed Width (ft)X Bed Length(ft) ,.o• � o.�e o.., 0.56 0.�. <br /> 1.5 0.22 0.51 0.69 0.9 <br /> 10 ft x 63 ft = 630 ft2 2°° °.�` °59 °�° ,.°' <br /> 2.5 0.29 0.65 0.H9 1.17 <br /> 3.0 0.32 0.72 0.98 1.28 <br /> Square Foot per Perforation =Bed Area divided by the Tota!Number of Perforations (Line 7). _.� �37 �8= , +_ +•� <br /> SA` p.qi 0.91 1.26 t-65 <br /> Z pweliings vn[h 3/Ib iM�t0 1/4 irKh <br /> 630 ft = 63 perforations = 10.0 ft2/perforations '`°°` o���d�w�� <br /> DweUing,vrich t/8 irx�pertora[iom <br /> 2�ee[ Oct�er es[aCti;hmenl5 and M5T5 wi[h 31t6 <br /> 9. Select Minimum Average Head: 1.0 ft inch to tia inch peAoraciof¢ <br /> 5 feec a�r cZtaDli:llmenl5 dnG M5T5 wl[h 1/9 inch <br /> pMoratartt <br /> 10. Select Perforation Discharge (GPM)based on Table I11: 0.56 GPM per Perforation <br /> 11• Determine required Flow Rate by multiplying the Toto(Number of Perforations (Line 7)by the Perforotion Discharge (Line 10). <br />