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OSTP Pressure Distribution <br /> UNIVERSITY , <br /> Minnesota Pollution Desi n W�rksheet *'`-�� _ - <br /> Control A enc g OF MINNESOTA �,���,� <br /> Project ID: v 11.09.22 <br /> 1. Setect Number of Perforated Latera(s in rystem/zone: � <br /> . . �,.,,,�.,�,.��.:,,,.:.�..., _ <br /> (2 feet is m�n►mum and 3 jeet is maximum spacing) <br /> �� -_` - - '� r _ <br /> 2. Select Perforotion Spacin3� 3.0 ft ' ' `5"' � ' - <br /> < �. <br /> ..��r.rir�r:�t�tr��s 4�:�c��d 3il:ili.�rt Mi��n�'rf 1z_ <br /> 3. Setect Perforation Diometer Size 7/32 in _ <br /> 5'ofro�k <br /> 4. Length of Loterals =Media Bed Length-2 Feet. �<.����.,���>���:��,,, �,. > �. P,�,<<,,.�i�o���n:,��,�n r„t' <br /> 63 - 2ft = 61 ft Perforation can not be doser then i foot from edge. <br /> 5- Determine the Number of Perforation Spaces. Divide the Length of Lotera(s (Line 4)by the Perforotion Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- ��ft = 20 Spaces <br /> 6. Number of Perforations per Laterai is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforotions Per Latero( = 20 Spaces + 1 = 21 perfs. Per Lateral <br /> Check tab(e be(ow to verify the number of perforations per lateral guarantees iess thon a f0%discharge voriation. The value is <br /> double if the a center manifo(d is used. <br /> Maximu.m Number of Fe�tecatiosu P�Latera[to Guarantee<1Q��scharge Variaiion <br /> �lnc�P�fcxani=�; 7!?1 Int!r P?rfarati�ns <br /> F��cration SFacng IF?�tl �p����``�''���'� Pe�faration Spacing Pipe D;arr�ter(lnchesl <br /> t i�! 11� 2 3 (Feetl { �t�, it� � � <br /> Z 1�5 13 18 3� 64 2 11 ib 2i 34 68 <br /> Z'" � !2 1 h 26 5�# 2 t 10 14 2C� 31 6�i <br /> 3 8 t2 16 25 52 3 9 14 19 30 60 <br /> 3;!1 b Inch Perorations t:8 Inch Pe�torat�om <br /> � Pi�a Diameter�Mchez) Fe�foration Sp�cing Pipe Qiameter(]nches) <br /> Pe,�c�rat:;on 5�,cng IF�tI <br /> 1 11•: t�. 2 3 (Feetl 1 i�: 9t; 2 3 <br /> 2 11 18 16 46 87 2 Zt 33 44 T4 149 <br /> �z� 12 t7 2�i 44 80 ��: 10 30 4t 69 135 <br /> � 12 16 21 31 75 3 20 29 38 64 12° <br /> 7• Tota(Number of Perforations equals the Number of Perforations per Latera( (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf. Per Lateral X ��Number of Perf. Laterats = 63 Totat Number of Perf. <br /> __ _. _ <br /> 8. Catculate the Square Feet per Perforation. Recommended value is 4-10 ftz per perforation. P�*'�•"°^°'�°h,��«P""� <br /> Does not app(y to At-Grades �<<aation Diameter <br /> Head(ft) _ <br /> ��a ��s ,�i r� <br /> Bed Areo = Bed Width(ft)X Bed Length(ft) ,.o• o.,$ 0.4, 0.56 0.�4 <br /> 1.5 0.32 O.St 0.69 0.9 <br /> 10 ft x 63 ft = 630 ftz Z.o° o.Zb o.s9 0.� ,.oa <br /> 2.5 0.29 0.65 0.89 1,17 <br /> 3.0 0.12 0.72 0.98 1.28 <br /> Square Foot per Perforotion =Bed Area divided by the Totol Number of Perforotions (Line 7). <.o 0.3� o.g3 ,.,3 ,.,� <br /> 5.0` 0.�1 0.93 1.2b 1.65 <br /> DwCllin [h 3/i6 inch[o t/4 irKh <br /> 630 ft2 - 63 perforations = 10.0 ft2/perforations '`°°` pertora w�� <br /> aveui�s wicn t is ixh peAoracio'rs <br /> 21eet p�tierr,tabti;hmi�ntsandM5T5with3176 <br /> 9. Select Minimum Average Head: 1.0 ft inch to t�4 inch pertoratior¢ <br /> 5 t�� Ocher eztabiishmrnts anO.MSTS wieh t/8 i'rch <br /> peAorat�orrs <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11. Determine required Flow Rate by multiptying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br />