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� � OSTP Pressure Distri ution <br /> �1NIVERSITY .� <br /> Minnesota Poliution Design Workshe t OF MINNBSOTA <br /> Control A enc ,��a.��.. <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Latera(s in system/zone: �� _ <br /> (2 feet is minimum and 3 feet is maximum spacing) ",,,,,`..,,", ,,,, <br /> � • '-� <br /> 2. Select Perforation Spacing: 3.0 f ' " „'` ' " - <br /> �• � <br /> (� Mir�irni��� <br /> �� /.._��ivlo�:�tiom�.��.�c�•cl 3':i��.�rt i".J'M rack j j=-�� <br /> 3. Setect Perforotion Diameter Size 7/32 � _ _ <br /> 6'nf��x-k <br /> 4. Length of Laterals =Media Bed Length-2 Feet. �'^����.,���^�,r�^�, '�- �•� �,>����.,���":��������:l «�� <br /> 63 - 2ft = 61 ft Perforation can ot be doser then 1 foot from edge. <br /> 5• Determine the Number of Perforation Spoces. Divide the Length of late als (Line 4) by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- 3 ft = 20 Spaces <br /> 6. Number of Perforations per Latera( is equal to 1.0 plus the Number of P rforation Spaces (Line 5). <br /> Perforations Per Lateral = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check table below to verify the number of perforations per(oteral guar ntees less thon Q 10%discharge variation. The value is <br /> double if the a center monifold is used. <br /> Maximum Nvmber of Ferforati�ns Pea�Lateral to Gua ntee<t�t D�scharge l�ariatio�n <br /> �lnth P�tc�a#ions 7`32 Inrh Pe�oracions <br /> Pipe Diarneter finches) Perfo tion Spacing Pipe Q;ametEr(Inchesk <br /> P?�fcrac:o�Spar:nq IFeat) <br /> 1 1s: 1'�� 1 ; (Feet) t tt; 1�; 2 3 <br /> Z 10 13 i8 30 60 2 11 15 21 34 68 <br /> �°: E 12 15 28 54 2t 10 1-0 2Q 32 64 <br /> 3 8 12 16 25 52 ? 9 14 19 3(} 60 <br /> ?.'16 Inch Perforaiiuns i�81nch Perfarations <br /> Pipe Diameier tinct�sl Ferfa tion Spacir� Pipe D�ame#er flnches) <br /> Ferforat�on Spat�n�iFertl <br /> 1 1Y. 1+< "t 3 iFe�eti 1 tt: tt: Z 3 <br /> 2 12 18 2fi 4b 87 2 21 33 44 74 149 <br /> It: 12 17 24 4�? $�J 2%: 24 3� �i b� i35 <br /> � 1t t6 22 37 75 3 20 ZQ 38 b4 12$ <br /> 7• Total Number of Perforations equals the Number of Perforations per Lat ra( (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf. Per Lateral X �Number of Pert. Laterals = 63 Total Number of Perf. <br /> 8. Calcutate the Squore Feet per Perforotion. Recommended vo(ue is 4-10 f � per perforation. P����•�b^DSSOAif�16°""� <br /> Does not apply to At-Grades PerforaHonDfameter <br /> Mcad(/t) <br /> ��a ��• '/�: �/. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) ,.o• o.,e o.a, 0.56 0.�. <br /> 1.5 0.22 0.57 0.69 0.9 <br /> 10 ft x 63 ft = 630 ft Z°° °.� °.5' °.� ,.°° <br /> 2.5 0.29 0.65 0.89 1.17 <br /> 3.0 0.32 0.72 0.98 1.28 <br /> Square Foot per Perforation =Bed Area divided by the Total Number of erforations (Line 7). <.o 0.3� 0.8� ,.,3 ,.4� <br /> 5A` O.it 0.93 1.26 1.65 <br /> 630 ftZ = 63 perforations = 10. ftZ/perforations �t�� �eo6 ro�th i/t6 inch to t/a irch <br /> DwelU�s vrith 1/8 inc�peAora[iom <br /> 2!ee[ O:her establizhments and ni,STS wi[h 3/�6 <br /> 9. Select Minimum Average Head: 1.0 ft inch to t/n inc�peAoratia�¢ <br /> 5 fcet aher e:tablk.hmen[s and hSTS with t/8 inch <br /> peAorntiona <br /> 10. Select Perforotion Discharge (GPM)based on Tabte III: 0.5 GPM per Perforation <br /> 11• Determine required F(ow Rate by multiplying the Tota(Number of Perfor tions (Line 7}by the Perforation Discharge (Line 10). <br />