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• • , F-17 <br /> PUMP SELECTION PROCEDURE <br /> END PERFORATION OF A PERFORATED LATERAL <br /> A. Determine pump capacity: W�Ca..r <br /> Gravity Distribution Topsoil J <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of _ <br /> Layer ofGeofertb <br /> Fale(or tar- <br /> water use rate. " Lew Sand LnInca I°' of o.pop.) <br /> Ira r r.Ovr XI <br /> on I.e rosin <br /> 2 Maximum suggested for deliveryto a dropbox of a home system is 2,700 ( -■ �.�A :clump..aIII.o Herr.....fif <br /> • p0-- Y r��• - -• Mro cav neer Too <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. , .,,.Pa. . -Al L.. l2•to Lair <br /> • FI.IA of Roc.pryer <br /> Perforation Lec0f.d of <br /> Pressure Distibution Clean Sane Layer Bottom of La1efOl <br /> 3.a. Select number of perforated laterals 3 <br /> l <br /> b. Select perforation spacing= ? feet arfa+•o sell Properly Screuloa <br /> Before Pbdnp Send Layer <br /> c. Subtra 2 ft_from the rock layer length. <br /> Rock Layer Ler.LaPL-2ft.= S3 feet. <br /> d. Determine the number of spaces between perforations. <br /> Length perf.spacing=,5Z ft.+ 3 ft.= I ') spaces Required Perforation Discharge <br /> e. I') spaces+ 1 = I'/ perforations/lateral in gallons per minute(gpm) <br /> f. Multiply perforations per lateral bye number of laterals to Discharge 3z m Per'� , 4 'd'am <br /> get total number of perforations. ,,--t.;-,, x 1,„,, ,,„,,,,- SY. perforations. (feet) <br /> g. x ser = gpm. <br /> 1.0a 0.56 0.74 <br /> SELECTED PUMP CAPACITY t D gpm 2.Ob 0.80 1.04 <br /> B.Determine head requirements: a. Use for single family homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applications <br /> "a,a feet <br /> 2. If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravityystem,zero. <br /> feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. ` Pipe Length <br /> Read friction loss in feet per 100 feet from table. Point of Discharge <br /> F.L.= ...l,H ft./100 ft of pipe T ms" <br /> b. Determine total pipe length from pump to discharge Elevation Difference <br /> point. Add 25 percent to pipe length for fitting pump -93 <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= F-18b <br /> a.'-1 U x 1.25= 3 00 feet <br /> c. Calculate total friction loss b multi 1 n 1.5 inch 2.0 inch 3.0 inch <br /> y p yl g gpm Fnaian lass per 100 ft of pipe <br /> friction loss in ft/100 ft by equivalent pipe length. <br /> Total friction loss= LI x 30 D =100=_ feet 10 0.69 0.20 <br /> 12 0-96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38 <br /> special head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> 20 2.47 0.73 0.11 <br /> a + J/ + cZ 25 3.73 1.11 0.16 <br /> (1) (2) - (3c) 30 5.23 1.55 0.23 <br /> 35 7.90 2.06 0.30 <br /> TOTAL HEAD v 40 11.07 2.64 0.39 feet 45 14.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> 55 4.76 0.70 <br /> C. Pump selection 60 5.60 0.82 <br /> 1. A pump must be selected to deliver at least <br /> y Cb gpm (Step A) with at least -�zs feet of total head (Step B). <br />