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1995 - 006973 - new septic system
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2760 White Oak Circle - 04-117-23-42-0018
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1995 - 006973 - new septic system
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Last modified
8/22/2023 5:14:07 PM
Creation date
2/3/2020 12:33:07 PM
Metadata
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Template:
x Address Old
House Number
2760
Street Name
White Oak
Street Type
Circle
Address
2760 White Oak Cir
Document Type
Septic
PIN
0411723420018
Supplemental fields
ProcessedPID
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G. • DOWNSLOPE DIKE WIDTH • <br /> 1. If landslope is 3% or more, subtract rock layer width from <br /> adsorption width to obtain minimum downslope dike toe <br /> ' .t..,9 ft- /0 ft = I') feet <br /> 2. Calculate Minimum mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation /. a feet Ca-k") <br /> b. Multiply rock layer width by landslope , I foot Cover <br /> to determine drop in elevation; . root Ro :ea <br /> Slope Difference �0��� Separation feet <br /> �,T}-4 , <br /> "''DJ Jo x (o % x- 100 = , ( feet Upslope white ---nomme Shope Difference _, et <br /> c. Add depth of dean sand for separation (2a) feet Rock Bed Width <br /> at upslope edge,depth of rock layer(1 foot) to depth of feet Downslope Width <br /> cover (1 foot) to find the mound height at the upslope edge feet <br /> of rock layer; <br /> )- ft + 1ft + lft= 3.--1, feet a L'7p )01.a's'\4 <br /> d. Enter table with landslope and upslope dike ratio. `-) .a �l-es�O - x 3.7 = /C. ' <br /> Select dike multiplier of 3. a'3 `t .9 epu..) 'SN-° .4 L4.. ._c- I <br /> e. Multiply dike multiplier by upslope mound height <br /> to find upslope dike width: 3.-L x 3.a. - = /D feet +x.1.07-�1-1/2-. <br /> f. Add depth of dean sand for slope difference (2b) at <br /> downslope edge, to the mound height at the upslope edge <br /> of rock layer (2c) to find the downslope height; <br /> -.-). ft + , L, ft=; .t feet <br /> g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of ,5"„-a. L <br /> h. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width: 3• x at. = D.D feet <br /> i. Compare the values of step G.1 and Step G.2h Select the <br /> greater of the two values as the downslope dike width; S ID -s))_= <br /> acs feet __. <br /> 0881008 W1oth; <br /> j. Total mound width is the sum of teat . <br /> s -'N- upslope dike (G.2e) width plus rock <br /> ,] } l0--I b= 4. layer width (D.2) plus = ups ooe width':: .i ostooe`width <br /> downslope dike width(G.2i); >J� � 3 test Leet <br /> ) ft+ 1° ft + .,o ft = 1-13 feet <br /> k. Total mound length is the sum of Downslope Width <br /> teat <br /> upslope dike width (G.2e) plus rock layer <br /> length (D.3) plus upslope dike width (G.2e); <br /> t3 ft + Ss ft + vi ft = 89 feet <br /> �.o .- .5".5 -r I 9 i <br /> Total Length <br /> Downslope L pslope <br /> 3:1 4:1 5:1 6:1 7:1 3:1 4:1 5:1 61 7:1 8:1 <br /> %slope <br /> 0 3.0 4.0 5.0 6.0 7.0 3.0 4.0 5.0 6.0 7.0 8.0 <br /> 1 3.09 4.17 526 6.38 753 2.91 3.85 4.76 5.66 6.54 7.41 <br /> 2 3.I9 (4.35 556 6.82 8.14 2.83 i70 454 536 6.14 6.90 <br /> 3 330 454 5.88 732 8.86 2.75 357 4.35 5.08 5.79 6.45 <br /> 4 3.41 4.76 6.25 7.89 9.72 263 3.45 4.17 4.84 5.46 6.06 <br /> 5 333 5.00 6.67 8.55710.77 261 4.00 4.62 5.19 5.71 <br /> 6 3.66 �S2b_ 7.14 938 1207 __ 3.85 4.41 4.93 5.41 <br /> 7 3.80 5.56 7.69 1034--"- -1373 -248 3.12 3.70 423 4.70 5.13 <br /> 8 3.95 5.88 8.33 1134 15.91 242 3.03 3.57 4.05 4.49 4.88 <br /> 9 4.11 6.25 9.09 13.04 18.92 236 294 3.45 3.90 430 4.65 <br /> 10 4.29 6.67 10.0 15.00 2333 231 2.86 333 3.75 4.12 4.44 <br /> 11 4.48 7.14 11.11 17.65 30.43 2.26 2.78 323 3.61 3.95 426 <br /> 12 489 7.69 12.50 21.43 43.75 2.21 2.70 3.12 3.49 3.80 4.08 <br />
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