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1996 - Septic System
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Wear Lane North
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040 Wear Lane North - 33-118-23-34-0010
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1996 - Septic System
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Last modified
8/22/2023 4:50:50 PM
Creation date
1/21/2020 11:34:33 AM
Metadata
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Template:
x Address Old
House Number
40
Street Name
Wear
Street Type
Lane
Street Direction
North
Address
40 Wear Lane North
Document Type
Septic
PIN
3311823340010
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ProcessedPID
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G. DOWNSLOPE DIKE WIDTH <br /> 1. If landslope is i,,% % or less adsorption width inculdes both upslope and <br /> downslope widths <br /> 2. Calculate Minimum mound size bsaed on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock layer: <br /> Separation -0 feet <br /> b. Multiply rock layer width by landslope t test Cover <br /> . t toot Ro ;ed <br /> to determine dropin elevation; <br /> S.p.rotton fest <br /> Slope Difference <br /> Steps Difference - et <br /> x --%j 100 = feet Upslope Width <br /> c. Add depth of dean sand for separation (2a) -__Lt,.-feet Root Bed Width <br /> at upslope edge, depth of rock layer (1 foot) to -JZ feet Downslope W10th <br /> depth of cover(1 foot) to find the mound height at the --L6-r"` <br /> upslope edge of rock layer; a.o ft+ lft + ift=, 4.0 feet <br /> d. Enter table with landslope and upslope dike ratio.' <br /> Select dike multiplier of y.0 <br /> e. Multiply dike multiplier by upslope mound height to find <br /> upslope dike width: y p x y. 0 _ 1 i' feet <br /> f. Add depth of dean sand for slope difference (2b) at downslope edge, to <br /> the mound height at the upslope edge of rock layer(2c) to find the <br /> :_ • downslope height; ----fr+ -- ft= feet <br /> . g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of . <br /> Y:`'; h. Multiply dike multiplier by downslope mound height to get <br /> downslope dike width: x = feet <br /> i. Minimum mound width is the sum of upslope dike width plus rock <br /> • layer width plus downslope dike width; <br /> _..._-ft-+ ftp__ _. ft - feet • :> <br /> z<::<;� '>::#?:upsiove wlatn>:: �;:::<.s�>.<>�:s::::<:z:�;>:r:>:;::>::::>:<:s>::»;::::::>::»:::»:;:»::::>::>:;::: <br /> feet <br /> width (21) from the > �<.<:<:.:::.�:.:.;.:::::.::>:.:>:.>:v.::::::.:.:::. ::: ..::::::. <br /> j. Subtract the minimum �.::.`.:::`:.':.:::' .. <br /> ..:.:.:::.:::.:::.. :.: <br /> adsorption do <br /> n are a F.4 tofind <br /> the <br /> additional <br /> "` wa sK se.o <br /> width <br /> downslope area for adsorption <br /> Ups..:lop eW. l <br /> Oln <br /> --ft=-. . . ft = feet UDsmolest <br /> _LJe.leet <br /> the <br /> 0 <br /> 2.' to y <br /> additional widthz <br /> the dditio <br /> k Add ( ) <br /> J <br /> . . <br /> downsolPe <br /> width andrecalculate :::...:.;::.:.:::::,...::,:::;;:.-;.;::.;::<.:•. <br /> :>'oe s e <br /> . <br /> W1818 . < <br /> the total width 1,12.._f.a <br /> 1 �� <br /> � ft ft ft = 4 <br /> feet <br /> 1. Total mound length is the sum of ` .. ......` <br /> upslope dike width plus rock layer length ;.<. <br /> plus upslope dike width: r) <br /> Total length <br /> llo ft + SS ft + /t, ft = '') feet <br /> Downslope Upslope <br /> 3:1 4:1 5:1 6:7 7:1 3:1 4:1 5:1 6:1 7:1 8:1 <br /> %elope <br /> 0 3.0 4.0 5.0 6.0 7.0 3.0 4.0 5.0 6.0 7.0 8.0 <br /> DI <br /> 1 3.09 4.17 576 6.38 753 2.91 3.85 4.76 5.66 654 7.41 <br /> 2 3.19 435 556 682 8.74 2ffi 3.70 4.54 5.36 61{ 6.90 <br /> 3 330 l54 5.88 732 8.86 275 337 4.35 5.08 5.79 6.0 <br /> 6. <br /> 4 3.41 4 76 6.25 7.89 9.72 268 3.45 4.17 4.84 5.46 09 <br /> 5 353 5.03 6.67 857 1077 261 333 4.03 4.62 5.19 511 <br /> 6 3.66 5.26 7.14 9.38 1207 254 3.73 3.85 4.41 4.93 5.41 <br /> 7 3.0 5.56 7.69 10.54 7373 2.48 3.12 3.70 423 4.70 5.13 <br /> 8 3.95 5.88 833 1154 15.91 242 3.03 357 4.05 4.49 4.88 <br /> 9 4.11 6.25 9.09 13.04 18.92 2.36 2.94 3.45 3.90 4.30 4.65 <br /> 10 419 667 10.0 15.00 23.33 2.31 2.86 333 3.75 4.12 4.44 <br /> 11 4.48 7.74 11.11 17.65 30.43 2.26 2.78 3.23 3.61 3.95 4.26 <br /> 12 4.69 7.69 1250 21.43 43.75 2.21 2.70 3.12 3.49 3.80 4.08 <br />
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