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MOUND DESIGN WORKSHEET <br /> ' (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(gpd) I <br /> Estimated L-c O gpd of Type I Type II Type Ill Type IV <br /> or measured - x 1.5 = - gpd. Bedrooms <br /> 2 300 225 180 sot <br /> 3 450 300 218 of <br /> B. SEPTIC TANK LIQUID VOLUMES • 4600 375 256 �;�. <br /> 5 750 450 294 ia <br /> 2--1 cod gallons 6 900 525 332 c''° <br /> 7 1050 6C0 370 :' <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) xtantxr ® <br /> 1. Depth to restricting layer = ) inches of <br /> Bedroo� ,'� w <br /> 2. Depth of percolation tests = ) cd'" inches `°"m•' (pilaw) <br /> or less 50 1,12.5 <br /> 3. Percolation rate 3s-, I mpi 23 or 444 1?.00 1..5500s0 <br /> 4. Land slope - % ,or g 3,003 <br /> over 9 See fig.C-6 (x 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> too o . gpd x 0.83 sq. ft./gpd = 4gw sq. ft.-H P2o Son <br /> 2. Select width of rock layer (10 feet or less) = 10 ft. <br /> 3. Length of rock layer= area_width = Rock Bed <br /> S 1-t' sq. ft. ÷ JO ft. = SS ft. a:;: -�-r <br /> rtir rtiftiftiftiJti:.V.fofofV.if`f1fofZ <br /> :;f;f;:ti:tiff.v.:•::tiv.f.t .v.v.fti'•tifWidth 510 ft. <br /> 5555555555555555555•555 J <br /> E. ROCK VOLUME Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 5L17 sq. ft. x l.os ft. =S'7LI cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 517 cu. ft. -27= a 1 cu. yd. • <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a ) cu. yd. x 1.4 ton/cu. yd. = Dc-7 tons. <br /> F. ADSORPTION WIDTH 61-14'-i t.,04v11 <br /> Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is ?S. I mpi Percolation Rate men• Ratio of <br /> Minutes per inch Soil Texture p„q�,� 10'',,,,"b <br /> (mpi) 1•e ab•wvea. <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> y J gpd/ft2 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 13. Calculate adsorption width ratio bydividingrock layer to 30 Loam 0.60 2.00 <br /> � 31}' 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 ClayLoam 0.45 2.67 <br /> 1.20 gpd/ft2÷ .0 S gpd/ft2 = D.V) . Slower thtO an 120 20 lay 0.24 5.00 <br /> "Soil having 50%or more."(fine or very fine sand. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 7.L, 1x �o ft= .)U.7ft <br /> 1 <br />