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1998-010783 - new septic
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1998-010783 - new septic
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Last modified
8/22/2023 4:30:07 PM
Creation date
12/13/2019 10:42:31 AM
Metadata
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Template:
x Address Old
House Number
4480
Street Name
Watertown
Street Type
Road
Address
4480 Watertown Road
Document Type
Septic
PIN
3111823240001
Supplemental fields
ProcessedPID
Updated
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4486 cti Ael) <br /> MOUND DESIGN WORKSHEET ôa3 .Jo f <br /> (For Flows up to 1200 gpd) <br /> f A. FLOW Estimated Sewage Flows in Gallons per d.. <br /> _ (&p1) <br /> Estimated X15 c' gpd 3 N Type1 Typen Type Ill Tyv <br /> or measured x 1.5 = gpd. Beate <br /> dr230 28110{ o � <br /> B. SEPTIC TANK LIQUID VOLUME ,.._. a eel 375 256vat <br /> Z - f GO o gallons ( La90_ J? s. 750 450 294 Y1 <br /> 6 0r <br /> 903 t 65332 j <br /> • 8 1200 675 408 w <br /> C. SOILS (refer to site evaluation) �p i,,t,,t Capacities(lo gallons)1. Depth to restricting layer= • (D 1nches _ _feet <br /> 2. Depth of Rercolation tests = ID-,.. inches Number of Minimum Liquid Liquid capacity with. <br /> f Bedrooina Capacity garbage disposal <br /> 3. Texture C ^ Percolatin rate 3 $• 1 mpi Vrwif 1125 <br /> 4. Land slope `�,d % 1000 1500 <br /> 2250 <br /> 7,8 or 9 . 2000 3000 <br /> 1 _ <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> Ak. <br /> q Cc gpd x 0.83 sq. ft./gpd =37 i sq. ft. 4-- /0 Of =` LH° <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = /0 ft. <br /> 3. Len th of rock layer = area +width/= �° ('� _ <br /> / sq. ft. = °raZI:n.P�46.:4. .01.3:5 $3,- q.v.. <br /> -_Ra,----------:---':WI <br /> °o„-.r ° c <br /> �_ft. ft. tcac•. a °u°..°g.v.o .vc vo ^..a <br /> a�°-w°a Q4 GD.OP Opti n.94� y0-n .</ Q°n.�°Q•n.n o rr <br /> ° <br /> . Width JO ft aQ : :: <br /> ° ° °•OQ•PPODP..°..°. .- °� <br /> .:° o .0 <br /> . 120mpi <10' Length / ' ft <br /> >120mpi <5' <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;f/O,sq. ft. x <br /> 1roft. = 'Pc' cu. ft. <br /> . 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 4-410 cu. ft. +27= IC cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; I cu. yd. x 1.4 <br /> ton/cu. yd. = i/tons. + fo 0 0 • <br /> Absorption Width Stang Table <br /> F. ABSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is- .1 mpi Percolation Rate in Gallons Ratio ofAbsurpu... <br /> p Mwutct pet Inch Soil Texture per day per width to Koch <br /> Texturee_<4�! 40A-,777. 7(-)-4-9- .5//6 - eo C) I / . (M?' rquare foot Laycr Width <br /> acyl q jZ Ja.cs SSC/h�/LQ Feta than 0.1 Coarse Sand 1.20 1.00 <br /> /' d / ter to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; ; 0.1 to S Fine Sand 0.60 . 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> a <br /> 16 30 Loans 0.60 2.00 <br /> p r.J.� gpd/ft2 shit am _ <br /> i ab to 60 .` ay(dam <br /> 5. <br /> 3. Calculate adsorption width ratio by dividing rocl'layer Sower than 120 Clay 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+a."3 gpd/ft2 = c.7. 7 . <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> v7,, 7 x /0 ft = 7 ft <br /> J <br />
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