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1998-010783 - new septic
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4480 Watertown Road - 31-118-23-24-0001
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1998-010783 - new septic
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Last modified
8/22/2023 4:30:07 PM
Creation date
12/13/2019 10:42:31 AM
Metadata
Fields
Template:
x Address Old
House Number
4480
Street Name
Watertown
Street Type
Road
Address
4480 Watertown Road
Document Type
Septic
PIN
3111823240001
Supplemental fields
ProcessedPID
Updated
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PRESSURE DISTRIBUTION SYSTEM Geotextile fabric <br /> 1. Select number of perforated laterals -----3 . s "'.i2 <br /> • arter inch . rforations s.aced @3' •• • <br /> 2. Select perforation spacing= —3 feet. .::•-•:',•.:.:.',97.0.1;04- . <br /> 3. Since perforations should not be placed closer than 1 ft. to - Perf Sizing 7/32" OA <br /> the edge of the rock layer (see diagram),subtract 2 ft. from Perf Spacings-5 <br /> the rock layer length. (4 3 <br /> .M- <br /> 6/ <br /> -2ft. _ -39 feet. <br /> Rock lay er length <br /> Raquusd Pert�uaoon Ducturte <br /> 4. Determine the number of spaces between perforations. �s Proo2 � <br /> uchu <br /> Divide.the length above by perforation spacing and round ° `` :s, , <br /> down to nearest whole number. r`t"" <br /> 4 ._l.u � 0.56 0.7, <br /> Length perf. spacing- J ft.= 3 ft. = 13 spaces 2.Ob 0.80 1.04 <br /> (3) (2) a.Use for single family homes <br /> b.Use for all other applications <br /> 5. Number of perforations is equal to one plus the number of <br /> perforation spaces . <br /> /3 spaces + 1 = �" perforations/lateral lateral Maximum tcee<10%r dischinch arge variatioerforations n <br /> Perforation <br /> 6. Multiply perforations per lateral by number of laterals to s(fee <br /> pacing <br /> 1 k lei 2 _ <br /> get total number of perforations. 2.5 14 28 <br /> �3 /`l _ 13 _-1) 26 <br /> l,�a s x pethiweral_"�� perforations. <br /> 3.3 12 16 25 <br /> • 7. Determine required flow rate by multiplying 4.0 11 15 23 <br /> number of perforations by flow ei erforation 5.0 10 14 22 <br /> pew x gpm/perfgpm. W�[OtD t.00ATED AT oo CO mownDsrmavtiom s+st[r <br /> ' .' <br /> 8. If laterals are connected to header pipe as shown on upper �, <br /> example, to select minimum required lateral diameter; enter .0-• <br /> table with perforation spacing and number of perforations ,,[s°' <br /> per lateral. Select minimum diameter for \�`� <br /> perforated lateral = inches. <br /> L..aR Of 141r04•i[D MK uT[.KS 10. <br /> ••t air.+nro+IN raw <br /> I.1.11W111.tRAM-' <br /> 9. If perforated lateral system is attached to manifold pipe near �`"`J =,•••' • • •• ''` <br /> tW , <br /> .[�. <br /> the center, lower diagram, perforated lateral length and rz.zt.«-- <br /> number of perforations per lateral will be approximately one '" :-- ._,7,=.4.1 <br /> half of that in step 8. Using these vales,select minimum "..., %, <br /> diameter for perforated lateral= I " inches. ,,�••`"`� �„:sem.. <br /> � i (6 <br /> a <br />
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