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2000-2748 - new septic
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2000-2748 - new septic
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Last modified
8/22/2023 4:40:29 PM
Creation date
11/4/2019 2:09:56 PM
Metadata
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Template:
x Address Old
House Number
3940
Street Name
Watertown
Street Type
Road
Address
3940 Watertown Road
Document Type
Septic
PIN
3211823320001
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Cellons pet Clay <br /> (nd <br /> Estimated YS-0 gpd ra,� �Type l Type nl Type In Type <br /> or measured x 1.5 = gpd. <br /> 2 300 215 180 60% <br /> B. SEPTIC TANK LIQUID VOLUMES 4 0 337050 256oftlie values <br /> Lallons ! 6 1 7900 52550 <br /> 52255 332 rya 1. <br /> 7 1050 600 370 p a <br /> 8 i 1200 675 408 ! 03 <br /> C. SOILS (refer to site evaluation) I `dam <br /> Tak (L � <br /> 1. Depth to restricting layer= o inches / feet �capacar <br /> •( t���� <br /> 2. Depth of percolation tests = �1 inches tt� � gat dmp-W lift inside <br /> ism <br /> 3. Texture aL Y 4:!jA- I Percolation rate 3 mpi 23 4 ow �" <br /> 4. Land slope _S % s•rV (500 MW loco <br /> 7.turY 2000 3000 •000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by-0-83 to obtain required area of rock layer.A x 0.83= <br /> Y�gpd x 0.83 sq. ft./gpd = 3 sv sq..ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') <br /> 3. Length of rock layer=area_width= =-x- •-W •-_- <br /> Ifiv sq. ft. - /D ft. hy- ft. <br /> Width.1ft <br /> <120mpi <10' Length 3f- ft <br /> E. ROCK VOLUME <br /> A 20mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;-3 to sq. ft. x v s' <br /> ft. = 91 cu. ft. <br /> 2. Divide cu. ft.by 27 cu.ft./cu. yd. to get cubic yards; <br /> cu.ft. =27=i•-cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;j�L cu. yd. x 1.4 <br /> ton/cu.yd. = 9% tons. <br /> F. ABSORPTION WIDTH Ahmptiou wtttm Sizing MdAe <br /> 1. Percolation rate in top 12 inches of soil is 3 mpi °°�m Gallons <br /> Texture Minutes per TQC <br /> lYl <br /> (MPI) square kot Layer width <br /> Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 0.1 to 5 Sand 1 20 1.00 <br /> 2. Select allowable soil loading rate from table; 0.1105 Fine Sand 0.60 2.00 <br /> �� gpd/ft2 6 to IS sandy Loam 0.79 1.52 <br /> 16 to 30 Loam 0.60 2.00 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60ro 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer Slower 6=120 MY 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2- ,y�r gpd/ft' <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> /D x D.7 ft =eft <br />
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